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djverab [1.8K]
3 years ago
8

Pls help, ill give brainliest

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

https://www.calculatorsoup.com/calculators/geometry-plane/polygon.php

that might help

Step-by-step explanation:

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The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 188 feet, what is the area of t
NemiM [27]

Answer: The area is 2,193 square feet (2,193 ft²)

Step-by-step explanation:The rectangular garden has its sides yet unknown but what we do know is that its length is 8 feet longer than its width. If therefore the width is W, then the length would be W + 8.

The perimeter is calculated as follows;

Perimeter = 2(L + W)

We can now substitute for the values given as follows;

188 = 2(W + 8 + W)

188 = 2(2W + 8)

188 = 4W + 16

Subtract 16 from both sides of the equation

172 = 4W

Divide both sides of the equation by 4

43 = W

If the width is 43, and the length is W + 8, then length equals 43 + 8 which gives us 51

Therefore the area is calculated as follows;

Area = L x W

Area = 51 x 43

Area = 2193

The area of the rectangular garden is 2,193 square feet

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4 years ago
Which of the following indicates a line segment?
Kazeer [188]

Answer:

A line segment is a line that starts somewhere and then ends somewhere.

Step-by-step explanation:

7 0
3 years ago
Which graph best represents the solution to the following pair of equations?
denpristay [2]
Second graph

explanation:
1. they both are increasing so only graph 1 & 4 fits
2. the y-intercept of y=x+5 is 5 so it’s graph 2
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3 years ago
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Look at this graph what is your slope?
n200080 [17]

Primero que bada ubicas las coordenadas de los puntos extremos para despues asi aplicando la siguiente formula encuentres su pendiente al igual que su angulo de inclinacion las formuas son m=X2-X1÷Y2-Y1 y angulo teta = Inv.Tan.teta la segunda formula es de la pendiente y la otra del angulo de inclinacion o teta

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4 years ago
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IF A+B+C=Π prove that sin(3A)+sin(3B)+sin(3C)=-4cos(3A÷2)cos(3B÷2)cos(3C÷2)​
Hunter-Best [27]

Answer:

LHS of the given equation is:

sinθ+sin3θ+sin5θ+sin7θ=(sinθ+sin7θ)+(sin3θ+sin5θ)=2sin8θ2.cos6θ2+2sin8θ2.cos2θ2   [since sinC+sinD=2sinC+D2.cosC−D2=2sin4θ.cos3θ+2sin4θ.cosθ=2sin4θ.[cos3θ+cosθ]       [since cosC+cosD=2cosC+D2.cosC−D2=2sin4θ.[2cos2θ.cosθ]=4cosθ.cos2θ.sin4θsinθ+sin3θ+sin5θ+sin7θ=(sinθ+sin7θ)+(sin3θ+sin5θ)=2sin8θ2.cos6θ2+2sin8θ2.cos2θ2   [since sinC+sinD=2sinC+D2.cosC-D2=2sin4θ.cos3θ+2sin4θ.cosθ=2sin4θ.[cos3θ+cosθ]       [since cosC+cosD=2cosC+D2.cosC-D2=2sin4θ.[2cos2θ.cosθ]=4cosθ.cos2θ.sin4θ

any more help just ask :)

Step-by-step explanation:

4 0
3 years ago
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