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3 years ago

Leslie bought an

Mathematics

2 answers:

andreev551 [17]3 years ago

7 0

The total cost would be $4

Evgen [1.6K]3 years ago

5 0

Answer:

$1.00

hopefuly this helped if not let me know!

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What is the answer and how to do this?

zhenek [66]

Answer:

a

Step-by-step explanation:

Given :

⇒ P (Sumit) = 1/2

⇒ P (Sujan) = 1/3

⇒ P (Rakesh) = 1/a

⇒ P (total) = 3/4

============================================================

Solving :

⇒ 1/2 × 1/3 × 1/a = 3/4

⇒ 1/6 × 1/a = 3/4

⇒ 2/12 × 1/a = 9/12

⇒ a = 9/2

6 0

2 years ago

At the afternoon matinee movie, 2 adult tickets and 4 child tickets cost $32, and 4 adult tickets and 3 child tickets cost $44.

Yuliya22 [10]

Answer:

2x + 4y = 32

4x + 3y = 44

Step-by-step explanation:

From the information supplied in the question, we can see that 2 adult tickets and 4 child tickets cost $32. This means we multiply the cost of an adult ticket by 2 and add it to the product of 4 child tickets and its price I.e y.

We can also see that to get a total cost of $44, 4 adult tickets and 3 child tickets were bought. Hence, we simply multiply the cost of an adult ticket by 4 and add it to the product of 3 child ticket and its price

8 0

3 years ago

Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)

bogdanovich [222]

Answer:

Answer is imaginary roots

Step-by-step explanation:

$({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\$

On solving the above mentioned equation we get some imaginary values.

 HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

3 years ago

BD bisects m m Find m

amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

$m\angle ABC = 77.2^\circ$

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

$m\angle ABD=m\angle CBD$

Substituting the algebraic expressions for both angles:

$2.5x + 8.6=3.5x - 3.4$

Subtracting 8.6 and 3.5x:

$2.5x - 3.5x = -8.6 - 3.4$

Operating:

$-x = -12$

$x = 12$

The two angles are:

$m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ$

$m\angle CBD=3.5x - 3.4 = 38.6^\circ$

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

$m\angle ABC = 2*38.6^\circ=77.2^\circ$

$\mathbf{m\angle ABC = 77.2^\circ}$

6 0

3 years ago

What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?

Margarita [4]

Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -2 &,& -4~) 
% (c,d)
&&(~ 3 &,& 8~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -2 &,& -4~) 
% (c,d)
&&(~ 3 &,& 8~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}
\\\\\\
d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad \stackrel{radius}{\frac{13}{2}}$

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad 
radius=\stackrel{\frac{13}{2}}{ r}
\\\\\\
\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}$

3 0

3 years ago

Read 2 more answers