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2 years ago

Which triangle has hypotenuse Side A E?

Mathematics

2 answers:

ira [324]2 years ago

8 0

Triangle GAE is correct

gtnhenbr [62]2 years ago

5 0

Answer:

OPTION D

Step-by-step explanation:

AS IN HAE ,AE IS THE GREATEST SUDE AND IN OPPOSITE TO RIGHT ANGLE,EXCEPT NO ONE FORMS RIGHT ANGLE IN ALL OPTIONS..

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How do i solve this problem to this fraction 2/3-1/6

dimulka [17.4K]

Find the common denominator of 3 and 6. which is 6. now just subtact 2 and 1 which is 1. ur answer is 1/6

4 0

3 years ago

Read 2 more answers

The expression 12x+8 represents the perimeter of a square write 12x+8 as a product then tell what expression represents one side

Pani-rosa [81]

Answer:

Step-by-step explanation:

Find the greatest common factor of 12x + 8

4(3x + 2) so one side is 4 and the other is 3x + 2

5 0

2 years ago

There is 2 questions. PLEASE HELP ME

attashe74 [19]

B and c I believe ..........

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id

taurus [48]

Answer:

$\boxed{\bf \: \cfrac{13}{5}}$

Or in Decimal:

$\boxed{\bf \: 2.6}$

Step-by-step explanation:

Given expression :-

$\sf \: ( 26 \div 100) \times 10$

Solution :-

$\sf = (26 \div 100 )\times 10$

This arithmetic expression may be rewritten as ;

$\sf = \cfrac{26}{100} \times 10$

Step 1 : Cancel the zero of 10 and one zero of 100 :-

$\sf = \cfrac{26}{10 \cancel0} \times 1 \cancel0$

Results to;

$\sf = \: \cfrac{26}{10} \times 1$

$\sf = \: \cfrac{26}{10}$

Step 2: Cancel 26 and 10 by 2 :-

$\sf = \cfrac{ \cancel{26}}{ \cancel{10}}$

Results to;

$\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }$

$\sf = \cfrac{13}{5}$

It can also be in Decimal.

That is;

$\sf = 2.6$

Hence, the answer of the expression would be 13/5 or 2.6 .

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

3 0

2 years ago

Read 2 more answers

HELP PLEASEEEEEEEEEeeeee

maks197457 [2]

Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.

3 0

3 years ago