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3 years ago

Find the set of values of x for which x^2-x-6>0 and 10-2x<5

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

No Solution.

Step-by-step explanation:

For starters, here are our two equations:

$(x^2-x-6)>0$

$10-2x$

The first option is to solve for x in our second equation. First, we add 2x to both sides to get $10$ . Then, we subtract 5 from both sides to get $2x$ . Finally, we divide both sides by 2 to get $x$ . We can plug in 2.5 into our second equation to test if it works. If it does not work, then anything less than 2.5 won't work, and the solution would be impossible.

Now we can plug in our values into our first equation. We now have the equation $2.5^2-2.5-6>0$ . We can simplify to get $-2.25>0$ . This test failed, so there are no solutions. A solution would be impossible.

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3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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3 years ago

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

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3 years ago

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pantera1 [17]

Answer:

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