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ycow [4]
3 years ago
10

0.486 Plus what equals 1.04

Mathematics
1 answer:
hammer [34]3 years ago
4 0

Answer:

0.554

Step-by-step explanation:

1.04-.486=0.554

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Explain the areas in which you will find integration to be significant in your day to day work as an EHT.
andrey2020 [161]

Answer:

Step-by-step explanation:

An EHT is an Environmental Health Technician. Integration (Integral Calculus, if that's what you mean) will be applied to an Environmental Health Technician's job in the following way:

1. In the analysis or examination of samples from an environment, such as soil sample, water sample, domestic waste sample, septic waste sample, etc.

Essentially, Integral Calculus (and other forms of Maths) must be studied, before a person is able to be an Environmental Health Technician.

Degrees in any of the following fields are a necessary criterion;

- Applied Science

- Public Health

- Environmental Science

- Biochemistry

- Health Data Analysis

7 0
3 years ago
Please help me I’m so lost !!!!
Tasya [4]

Answer:

4095

Step-by-step explanation:

\sum _{n=1}^63\left(4^{n-1}\right)\:

\sum _{n=1}^63\cdot \:4^{n-1}

Compute general progression:

\frac{3\cdot \:4^{\left(n+1\right)-1}}{3\cdot \:4^{n-1}}=4

r=4\\

a_1=3\cdot \:4^{1-1}

a_1=3

nth term is computed by:

r=4,\:a_n=3\cdot \:4^{n-1}

plug in the values n=6,\:\spacea_1=3,\:\spacer=4:

=3\cdot \frac{1-4^6}{1-4}

=4095

5 0
3 years ago
Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o
umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that  

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So  

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now  

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)  

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)  

1/2 ∫▒(2xdx/u) =1/2  ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2  ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C  (required soultion)

3 0
3 years ago
Read 2 more answers
What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1?
zimovet [89]
Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=1\\
k=2\\
p=1
\end{cases}\implies 4(1)(y-2)=(x-1)^2\implies 4(y-2)=(x-1)^2
\\\\\\
y-2=\cfrac{1}{4}(x-1)^2\implies y=\cfrac{1}{4}(x-1)^2+2

4 0
3 years ago
A+B share a ratio of 2:3 A pays 126 how much does B pay
Alenkasestr [34]
A:B = 2:3

A=126
B=?

126/2=63

63x3=189

A=126
B=189

A:B = 126:189
6 0
3 years ago
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