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makkiz [27]
3 years ago
15

A dolphin can swim 60 miles per hour . what is this speed in feet per hour

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

Dang that dolphin is fast. I wanna go to japan on that dolphin

Step-by-step explanation:

:o

qaws [65]3 years ago
4 0

Answer:

5280 feet

Step-by-step explanation: Hope this helps!

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A Salt Marsh Harvest Mouse ran a 360 centimeter straight course race in 9 seconds. How fast did it run?
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Step-by-step explanation:

360/9 = 40

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I have 5 quarters and 7 pennies. What fraction of the coins are pennies?
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What number is exactly halfway between 1000 and 1500?
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the \ number \to \frac{1000+1500}{2}=\frac{2500}{2}\to\boxed{\boxed{1250}}
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Help!
Thepotemich [5.8K]

Answer:

The median is 10 and the mean is 10.2

Step-by-step explanation:

Median: the middle number -> 6,8,10,11,16

Mean:

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3 years ago
In a​ study, researchers wanted to measure the effect of alcohol on the hippocampal​ region, the portion of the brain responsibl
schepotkina [342]

Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

6 0
3 years ago
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