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Tresset [83]
2 years ago
7

Constance ran 620 meters around 4 sides of a square field. How many meters long was each side of the field?

Mathematics
1 answer:
kumpel [21]2 years ago
5 0
155 meters is the answer. You have to divide 620 by 4.
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Which of the following is not a tool that can be used in a true Geometric construction? a)Protractor b)Compass c)Straightedge
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Answer:

A) Protractor

Step-by-step explanation:

In Mathematics, geometric constructions refers to the drawing of geometric shapes, lines and angles with the exclusive aid of a pencil, straightedge/ruler and a pair of compass.

The pencil is the major drawing tool during the construction while the pair of compass and straightedge are used to construct arcs/circles and straight lines respectively. Note that, a PROTRACTOR is not needed in a geometric construction because length or angle measurements are prohibited.

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The forst digit in the quotient of 1,875÷9 will be in the blank place
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The first digit in will be in the hundreds place.
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(2) The population density of a region in Alaska is 3,000 people/200 mi? Which of the
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Answer:

15 people/mi

Step-by-step explanation:

The population density of a region in Alaska is 3,000 people/200 mi.

We need to find the equivalent to the population density of this Alaskan region.

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Will give brainliest! 20 Points!<br> Hi! Some help with these problems would be great thank you!
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Answer:

<u>Question 1:</u>

Draw a line that crosses the largest number of dots. Then use the line to check the best prediction of the number of baseballs that will be used if 275 pitches are thrown.

<u>Question 2:</u>

A). y = 1.2x - 6

<u>Question 3:</u>

J). y = \frac{9}{4}x - 81

<u>Question 4:</u>

F). f(n) = -3n + 24 *<em>Although it doesn't work when f(n) = 6 and n = 6*</em>

<u />

Step-by-step explanation:

<u>Question 2:</u>

The line passes throught point (5, 0) and is parallel to the line whose equation is y = 1.2x + 3.8

For parallel lines, their values of slope is the same.

So our line, that passes through point (5, 0), also has a slope of 1.2

Taking another point (x, y) on our line;

Slope = change in y ÷ change in x

1.2 = \frac{y - 0}{x - 5}

y = 1.2x - 1.2(5)

y = 1.2x - 6

<u>Question 3:</u>

The line passes x-axis at point (36, 0)

The line is perpendicular to another line whose equation is y = -\frac{4}{9}x + 5

For perpendicular lines, the product of their slopes = -1

Let's say the slope of our unknown line is a ;

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a × -4/9 = -1

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Taking another point (x, y) on our unknown line;

Slope = change in y ÷ change in x

9/4 = \frac{y - 0}{x - 36}

Cross-multiplying that you get;

y = \frac{9}{4}x - 81

<u>Question 4:</u>

The function that model that situation is f(n) = -3n + 24 though it doesn't work when f(n) = 6 and n = 6

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Step-by-step explanation:

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