Answer: 2x^2-7x-15
Step-by-step explanation:
reorder the terms (x*2+3)*(x-5)
multiply the parentheses
(2x+3)*(x-5)
collect like terms (2x^2-10x+3x-15)
product= 2x^2-7x-15
Answer:
0.285
Step-by-step explanation:
To do this, divide 28 1/2% by 100%, obtaining:
28.5%
---------- = 0.285
100%
Answer: f(-3) = 2 x -3 = -6
<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,

As,




Therefore, the vertex at K (-4, 8) is the orthocentre.