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xz_007 [3.2K]
3 years ago
12

A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred

ient are used?
Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:  0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = \dfrac{0.63}{3}

=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

2\times0.21=0.42\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

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