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4 years ago

12

A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred

ient are used?

1 answer:

Sergio039 [100]4 years ago

6 0

Answer: 0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = $\dfrac{0.63}{3}$

$=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

$2\times0.21=0.42\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

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Question 2:

Let's solve your equation step-by-step.

5−1(2x+3) =−2(4+x)

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