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mihalych1998 [28]
3 years ago
7

Help find the answer please

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

I think the answer is E.

Step-by-step explanation:

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The measure of an angle exceeds 6 times its supplement by 5. find the measure of the angle
MArishka [77]
Supplementary angles must add to 180 degrees. Let x and y be the measure of the two angles.

y= 6x+5
x+y=180

Substitute y
x+6x+5=180
7x+5=180
7x=175
x=25

Plug the value of x in
25+y=180
y=155

Final answer: 155 degrees
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3 years ago
Tyrone spends $2 on ingredients for every $7 of revenue he collects selling sandwiches at his shop. Tyrone collects $2100 sellin
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Answer:

  • $1500

Step-by-step explanation:

Tyrone spends $2 on ingredients for every $7 of revenue.

<u>The profit is:</u>

  • $7 - $2 = $5

<u>Fraction of profit:</u>

  • 5/7

<u>Profit for the day:</u>

  • $2100*5/7 = $1500
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2 years ago
Em dois retângulos semelhantes, a ampliação foi de 10 cm por 12 cm, para 20 cm por 24 cm, qual a razão de semelhança (K)?
Semenov [28]

Answer:

1,2

Step-by-step explanation:

4 0
3 years ago
4 groups of 9 write the equation
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9x4=? Because there are 4 groups of 9 so it is multiplication.<span />
8 0
4 years ago
Read 2 more answers
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
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