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3 years ago

Help find the answer please

Mathematics

1 answer:

Trava [24]3 years ago

8 0

Answer:

I think the answer is E.

Step-by-step explanation:

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The measure of an angle exceeds 6 times its supplement by 5. find the measure of the angle

MArishka [77]

Supplementary angles must add to 180 degrees. Let x and y be the measure of the two angles.

y= 6x+5
x+y=180

Substitute y
x+6x+5=180
7x+5=180
7x=175
x=25

Plug the value of x in
25+y=180
y=155

Final answer: 155 degrees

4 0

3 years ago

Tyrone spends $2 on ingredients for every $7 of revenue he collects selling sandwiches at his shop. Tyrone collects $2100 sellin

Reika [66]

Answer:

$1500

Step-by-step explanation:

Tyrone spends $2 on ingredients for every $7 of revenue.

The profit is:

$7 - $2 = $5

Fraction of profit:

Profit for the day:

$2100*5/7 = $1500

3 0

2 years ago

Em dois retângulos semelhantes, a ampliação foi de 10 cm por 12 cm, para 20 cm por 24 cm, qual a razão de semelhança (K)?

Semenov [28]

Answer:

1,2

Step-by-step explanation:

4 0

3 years ago

4 groups of 9 write the equation

pishuonlain [190]

9x4=? Because there are 4 groups of 9 so it is multiplication.

8 0

4 years ago

Read 2 more answers

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago