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Sati [7]
3 years ago
13

Mr. Cresta spends $6.00 for every $3.00 he saves. Write a ratio equivalent to Mr. Cresta's spending

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

12:6 or $12 for every $6 he saves

Step-by-step explanation:

If he spends $6.00 for every $3.00, he would save $6 if he spends $12. In this case you could multiple or divide 6 by any number, and do the same to 3 to get an equivalent ratio. Ex. Multiple 6 times 2 to get $12 and 3 times 2 to get $6.

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Answer:

The numerator factors to

(x + 2)(x - 1)

The denomenator factors to

(x + 4)(x - 1)

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There is 4/6 of a pizza left from dinner . Each person gets 1/6 of a pizza for lunch the next day . How many people eat the pizz
kolezko [41]

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4 people eat the pizza for lunch

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1 year ago
Help Me within 10-15 Minutes and you have a 50/50 chance of getting an unbiased brainliest
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3 years ago
Richard bought 32.4 pounds of potting soil and 45.6 pounds of sand. She got the potting soil for $0.86 per pound and the sand fo
frozen [14]

Answer:

67.00

Step-by-step explanation:

Add the numbers.

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3 years ago
A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. (a) The card drawn is 5. The pro
Dmitrij [34]

Answer:

  • a. 1 / 13
  • b. 3 / 13
  • c. 10 / 13

Step-by-step explanation:

<h3>a.</h3>

There are four 5's in the deck. This means that, from 52 possible cards to drawn, we have 4 chances of drawing a 5. This means that the probability will be:

p = \frac{4}{52}

p = \frac{1}{13}

<h3>b.</h3>

For every suit, there are three face cards, J, Q and K. There are 4 suits, so, the total number of face cards its:

4 * 3 = 12

The total possible cards are, still, 52, so, the probability will be

p = \frac{12}{52}

p = \frac{3}{13}

<h3>c.</h3>

We know that the card drawn must be a face card, o not being a face card. There is no third choice here. So, the probability of drawing a face card OR not drawing a face car its:

p = \frac{52}{52} = 1

so

p(the \ card \  is \  a \  face  \ card) + p(the \ card \  is \  not \ a \  face  \ card) = 1

p(the \ card \  is \  not \ a \  face  \ card) = 1 - p(the \ card \  is \  a \  face  \ card)

but, we know that

p(the \ card \  is \  a \  face  \ card = \frac{3}{13}

so

p(the \ card \  is \  not \ a \  face  \ card) = 1 - \frac{3}{13}

p(the \ card \  is \  not \ a \  face  \ card) = \frac{10}{13}

7 0
3 years ago
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