Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A similar question is attached and is solved.
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are scalene, acute, obtuse, isosceles, equilateral and right angled triangle.
A right angled triangle is a triangle with one angle equal to 90 degrees. The longest side of a right angled triangle is known as the hypotenuse. Trigonometric identities is used to show the relationship between the angles and sides of a right angled triangle, i.e.:
sinθ = opposite/hypotenuse; cosθ = adjacent / hypotenuse; tanθ = opposite / adjacent
From the image:
let the distance from jack to the base of the building be x, hence:
tan60 = x / 60
x = 60 * tan60 = 104 ft.
36 free throws , 16 games
ratio of free throws to games is 36:16 which reduces to 9:4
u have to pay attention to the wording of problems such as these..because if it would have asked for the ratio of games to free throws, it would have been 16:36 = 4:9
In piecewise linear functions, the endpoint of one segment and the initial point of the next segment can have the same x-coordinate but a different value of f(x).
Such difference in values is called a step or discontinuity and such a function is called a discontinuous function.
Here in this case, there are 3 discontinuities: x=-3, x=3 and x = 5.
x = -3 because x is smaller than or greater than -3 but not equal.
x = 3 since greater than 3 in one of the inequalities.
x = 5 since x is smaller than 5 in one of the limits.
4(r)^x=y
4(r)^(1)=2
r=1/2
y=4*(1/2)^x
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
