What is the exact volume of the cylinder enter your answers in the term of pie in the Box 5cm 15cm

Could you please explain find an equation for i, -i, -4, 1 = x as its solution

Virty [35]

We can do this easily using 0s.

(x - i) (x + i) (x + 4) (x - 1) = 0

If you plug in any of the numbers, you'll get 0, making the equation true.

5 0

3 years ago

Confusion...help please

kifflom [539]

Given:

In triangle KLM, KL = 123 cm and measure of angle K is 35 degrees.

To find:

The length of the side KM to the nearest tenth of a centimeter.

Solution:

In a right angle triangle,

$\cos \theta =\dfrac{Base}{Hypotenuse}$

In the given right triangle KLM,

$\cos K=\dfrac{KM}{KL}$

$\cos (35^\circ)=\dfrac{KM}{123}$

$0.819152=\dfrac{KM}{123}$

Multiply both sides by 123.

$0.819152\times 123=KM$

$100.755696=KM$

$KM\approx 100.8$

The measure of side KM is 100.8 cm.

Therefore, the correct option is (2).

8 0

3 years ago

3*(2)=6+5 3*(2+5) Please help

Lina20 [59]

Answer:

6 = 413 is a not true statement

Step-by-step explanation:

I've attached my work below

Hope it helps, Let me know if you have any questions/concerns !

Have a nice rest of your day :)

4 0

3 years ago

22. One kilometer is approximately 0.62 mile. What fraction represents this length?

bixtya [17]

Answer:

One kilometer is $\frac{31}{50}$ miles

Explanation:

To convert a decimal to a fraction:

1- Write the decimal as a fraction whose denominator is 1

2- Multiply both numerator and denominator by multiples of 10 to eliminate the decimal point

3- Simplify the fraction you have

Now, for the given problem:

The given decimal is 0.62, following the above steps:

Step 1:

$0.62 = \frac{0.62}{1}$

Step 2:

We have two digits after the decimal point, so to eliminate the decimal point, we will multiply the numerator and the denominator by 100

$0.62 = \frac{0.62}{1} * \frac{100}{100} = \frac{62}{100}$

Step 3:

We can note that, in the fraction obtained from step 2, both the numerator and the denominator are divisible by 2, so we simplify as follows:

$\frac{62}{100} = \frac{62/2}{100/2} =\frac{31}{50}$

Hope this helps :)

6 0

3 years ago

Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar

Mamont248 [21]

Answer:

a

The 95% confidence interval is

$0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

c

$n = 125 \ stores$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The number of stores that had more than 2 items price incorrectly is k = 52

Generally the sample proportion is mathematically represented as

$\^ p = \frac{ k }{ n }$

=> $\^ p = \frac{ 52 }{ 60 }$

=> $\^ p = 0.867$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.867 (1- 0.867)}{60} }$

=> $E = 0.0859$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.867 - 0.0859 < p < 0.867 + 0.0859$

=> $0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Considering question b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

Considering question c

From the question we are told that

The margin of error is E = 0.05

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n= [\frac{1.645 }}{0.05} ]^2 * 0.867 (1 - 0.867 )$

=> $n = 125 \ stores$

4 0

3 years ago

What is the exact volume of the cylinder enter your answers in the term of pie in the Box 5cm 15cm​

What is the exact volume of the cylinder enter your answers in the term of pie in the Box 5cm 15cm