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Citrus2011 [14]

3 years ago

14

Bret works for a printing company. He buys 5 packs of card. Each pack of card costs £14.06 How much money does Bret pay in total

for the packs of card? Use the correct money format

1 answer:

klasskru [66]3 years ago

8 0

Multiply 5 and £14.06 to get £70.30 this is your answer

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What is the answer to -3.4 - 1.6?

NeX [460]

Answer:

-5

Step-by-step explanation:

-3.4 - 1.6 = -5

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2 years ago

What is the sum of all measures of the interior angles of a regular pentagon?

Ugo [173]

There are 540 degrees total in the interior angles of a regular pentagon.

Just so you know, the total degrees of interior angles goes up by 180 degrees.

A triangle is 180 degrees, a quadrilateral 360, and a pentagon 540.

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3 years ago

The soccer team sells 54 bagels with cream cheese for $2 each and 36 muffins for $1 each during a bake sale.The coach uses the m

Jlenok [28]

54•2=108
36•1=36
108+36=144
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Answer is $56.00

7 0

3 years ago

Read 2 more answers

HELP ME ASAP!!!!!!!!

coldgirl [10]

Step-by-step explanation:

a. 6 £/hr

b. 6.8 £/hr.....is this right?

8 0

3 years ago

Read 2 more answers

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

3 years ago