Question

The number of traffic violations in a city increased from 12 to 16 in a month. What is the percent of increase in the number of traffic violations for that month? Round to the nearest percent, if necessary.

Answer 1

Answer:

33%

Step-by-step explanation:

Percentage increase = $\frac{increase}{initial value}$ x 100%

Number of traffic violations increased from 12 to 16.

Initial value = 12

Final value = 16

increase = Final value - Initial value

              = 16 - 12

              = 4

Percentage increase = $\frac{increase}{initial value}$ x 100%

                                    = $\frac{4}{12}$ x 100%

                                    = $\frac{1}{3}$ x 100%

                                    = $\frac{100}{3}$%

                                    = 33.3333%

The percentage increase in the number of traffic violations for the month is 33%.