I mole of water has an Avogadro number of molecules.

1 mole = 6.02 * 10^ 23 molecules.

6.02 * 10^ 23 molecules = 1 mole of water

1 molecule = 1/(6.02 * 10^23) mole of water

2.0 * 10^22 molecules would have = (2*10^22) * 1/(6.02*10^23)

= 0.033

2* 10 ^22 molecules of water would have 0.033 moles of water.

5 0

3 years ago

1. _ LiBr2 + __K2CO3 -->___ LiCO3 +_ KBr<br> Reaction Type:

Arada [10]

Answer:

Double displacement chemical reaction.

Explanation:

Hello,

In this case, for the given reaction we firstly balance it:

$LiBr_2 +K_2CO3 \rightarrow LiCO3 +2KBr$

Then, since the lithium and potassium cations are being exchanged to each other from bromide and carbonate, we are talking about a double displacement chemical reaction.

Best regards.

5 0

4 years ago

How does a salt bridge improve a battery

jonny [76]

The role of the salt bridge is to assure the neutrality of both compartments.

6 0

3 years ago

Read 2 more answers

The plot shows the absorbance spectra for solutions of caffeine, benzoic acid, and Mountain Dew® soda, each in 0.010 M HCl . A p

Aliun [14]

Complete Question

The diagram of the complete question is shown on the first uploaded image.

Answer:

a) The approximate absorbance of benzoic acid at 228 nm? : A = 0.8

b) The molar absorptivity(∈)

of benzoic acid at 228 nm? : ∈ = $1.12 * 10^{4} M^{-1} cm^{-1}$

Explanation:

Looking at the absorbance spectra, we can see that the approximate absorbance of benzoic acid at 228 is 0.8.

mass concentration of benzoic acid = $8.74 \frac{mg}{L} =8.74 * 10^{-3} \frac{g}{L}$

the molar concentration of benzoic acid = (mass concentration of benzoic acid) / (molar mass of benzoic acid )

molar concentration of benzoic acid = $(8.74 *10^{-3} \frac{g}{L} ) /(122.12\frac{g}{mol} )$

molar concentration of benzoic acid = $7.157 * 10^{-5}M$

molar absorptivity (∈) of benzoic acid = (absorbance) /[ (molar concentration of benzoic acid ) × (path length) ]

∈ = (0.8) / [ ( $7.157 *10^{-5}M$ ) ×(1.00 cm)]

= $1.12 * 10^{4} M^{-1} cm^{-1}$

5 0

3 years ago