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3 years ago

Write the other side of this equation so that this equation

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

Answer: 6(u-2)+2=6u-10

Step-by-step explanation:

Then, any value of u makes the equation true.

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if all of the medians of a triangle were constructed, what would the point where they all intersect be called?

Lubov Fominskaja [6]

Answer:

i think its centroid not sure though.

Step-by-step explanation:

3 0

4 years ago

the diagram, JG = 5 cm and GE = 10 cm. Based on this information, can G be a centroid of triangle HJK?

SIZIF [17.4K]

Point G cannot be a centroid because GE is wider that JG or JG is shorter than GE. So in this diagram GE is wider than JG with 10 cm and 5 cm respectively based on this information Point G cannot be a centroid of triangle HJK. So the answer is point G cannot be a centroid because JG is shorter than GE.

4 0

3 years ago

Read 2 more answers

Write the prime factorization of the number. 18,234

shusha [124]

Answer:

$18234=2\times 3\times 3\times 1013$

Step-by-step explanation:

We are given that a number 18234

We have to find the prime factorization of the number

Prime factorization : The number written is in the product of prime numbers is called prime factorization.

In order to find the prime factorization we will find the factors of given number

$18234=2\times 3\times 3\times 1013$

Hence, the prime factorization of $18234=2\times 3\times 3\times 1013$

3 0

3 years ago

Describe fully the single transformation that maps triangle A onto triangle B

Anvisha [2.4K]

Answer:

180 degree clockwise rotation about center and a dilation of 0.5.

5 0

3 years ago

In how many ways can 3person study groups beselected from a class of 25students?Note: nrn!r!(n-r)!nEnter

nlexa [21]

Answer:

2,300

Explanation:

This is given as:

$\begin{gathered} 25\text{ combination 3 represented as:} \\ ^nC_r=\frac{n!}{r!(n-r)!} \\ n=25 \\ r=3 \\ ^{25}C_3=\frac{25!}{3!(25-3)!} \\ ^{25}C_3=\frac{25\times24\times23\times22!}{3!\times22!} \\ ^{25}C_3=\frac{25\times24\times23}{3\times2\times1} \\ ^{25}C_3=2300 \end{gathered}$

Therefore, there are 2,300 ways that 3 persons can be selected from 25 people

8 0

1 year ago