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dmitriy555 [2]
3 years ago
10

Describe the transformation of the graph of the parent function y= sqrt x+7 + 5​

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer:

The function moves 7 to the left and 5 units up

Step-by-step explanation:

y = (x + 7) + 5

I think that's the problem you put.

Elena L [17]3 years ago
5 0

Answer:

Left and Up

Step-by-step explanation:

Correct on edg :)

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Answer:

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Step-by-step explanation:

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Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 o
dimulka [17.4K]

Answer:

The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.

Step-by-step explanation:

The amount of water in the tank after 15 days is given by the series

910+(−710)+810+(−610)+⋯+310+(−110)+210

From the series, we can observe that, if water is added for a particular day then water will be drained the following day.

Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.

Hence, we can complete the series thus:

910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210

To evaluate this, we  get

910-710+810-610+710-510+610-410+510-310+410-210+310-110+210

= 1610.0 gallons

Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.

8 0
3 years ago
Please help will mark brainliest if correct
sesenic [268]

Answer:

Step-by-step explanation:

<u><em>The triangles can not be proven congruent.</em></u>

We have AAA theorem ⇒ given triangles are similar for sure.

3 0
3 years ago
Compound interest of $1000 is invested at 10% compounded continuously, the future value s at any time t in years is given by s=1
crimeas [40]

Answer: 6.93 years

Step-by-step explanation:

Given

Rate of interest is r=10\%

Future value is given by s=1000e^{0.1t}

For the investment to double itself, i.e. s=2000

\Rightarrow 2000=1000e^{0.1t}\\\Rightarrow 2=e^{0.1t}\\\\\text{Taking log both sides}\\\\\Rightarrow \ln 2=0.1t\\\\\Rightarrow t=\dfrac{\ln 2}{0.1}\\\\\Rightarrow t=6.93\ \text{years}

It takes around 6.93 years to double the investment.

8 0
2 years ago
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