How many moles are there in 3.04 X 10^23 molecules of hydrogen, H2, gas?

How does heat transfer occur?

Sphinxa [80]

I believe your answer is D

7 0

4 years ago

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List 6 uses of acids

devlian [24]

Answer: 1. Vinegar, used in the kitchen, is a liquid containing 3-6% acetic acid. It is used in pickles and in many food preparations.

2. Lemon and orange juice contains citric acid. Citric acid is used in the preparation of effervescent salts and as a food preservative.

3. Acids have been put to many uses in industry. Nitric acid and sulphuric acid are used in the manufacture of fertilizers, dyes, paints, drugs and explosives.

4. Sulphuric acid is used in batteries, which are used in cars, etc. Tannic acid is used in the manufacture of ink and leather.

5. Hydrochloric acid is used to make aqua regia, which is used to dissolve noble metals such as gold and platinum.

6. Sulphuric acid is used in manufacturing fertilizers such as super phosphate, ammonium sulpahte etc.

8 0

3 years ago

Calculate the energy that is required to change 50.0 g ice at -30.0°C to a liquid at 73.0°C. The heat of fusion = 333 J/g, the h

OverLord2011 [107]

Answer:

There is 3.5*10^4 J of energy needed.

Explanation:

Step 1: Data given

Mass of ice at -30.0 °C = 50.0 grams

Final temperature = 73.0 °C

The heat of fusion = 333 J/g

the heat of vaporization = 2256 J/g

the specific heat capacity of ice = 2.06 J/gK

the specific heat capacity of liquid water = 4.184 J/gK

Step 2: Calculate the heat absorbed by ice

q = m*c*(T2-T1)

⇒ m = the mass of ice = 50.0 grams

⇒ c = the heat capacity of ice = 2.06 J/gK = 2.06 J/g°C

⇒ T2 = the fina ltemperature of ice = 0°C

⇒ T1 = the initial temperature of ice = -30.0°C

q = 50.0 * 2.06 J/g°C * 30 °C

q = 3090 J

Step 3: Calculate heat required to melt the ice at 0°C:

q = m*(heat of fusion)

q = 50.0* 333J/g

q = 16650 J

Step 4: Calculate the heat required to raise the temperature of water from 0°C to 73.0°C

q = m*c*(T2-T1)

⇒ mass = 50.0 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = T2-T1 = 73.0 - 0 = 73 °C

q = 50.0 * 4.184 * 73.0 = 15271.6 J

Step 5: Calculate the total energy

qtotal = 3090 + 16650 + 15271.6 = 35011.6 J = 3.5 * 10^4 J

There is 3.5*10^4 J of energy needed.

8 0

3 years ago

What is the mass of KNO3(s) that must dissolve in 100. grams of water to form a saturated solution at 50.oC?

Ostrovityanka [42]

The solubility of substance depends upon the temperature. In present case, the solubility of KCl is 84g/100g at 50.oC.

This means that, maximum 84g of KCl can be dissolved in 100g of water (at 50.oC) to form solution. This solution is referred as saturated solution.

Thus, 84g of KNO3 must be dissolve in 100 grams of water to form a saturated solution at 50 oC.

4 0

4 years ago

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I don’t need the answers to this but u can if u want but I’m just asking what is this is asking for and how to solve it? I hope

strojnjashka [21]

Answer:

See explanation

Explanation:

Salts are produced from the reaction of an acid and a base. In general ...

Acid + Base => Salt + Weak Electrolyte

Acids from the 'Arrhenius Definition' contain an 'ionizable' hydrogen (-H). Such as, HCl, HBr, HI, HNO₃, HClO₄, HF, etc.

Bases from the 'Arrhenius Definition' contain an 'ionizable' hydroxide (-OH). Such as, LiOH, NaOH, KOH, CsOH, Ca(OH)₂, etc.

When the acid and base react, they proceed by what is known as a 'Double Replacement Reaction' or 'Metathesis Reaction'. In the process, the ions of the reactant compounds exchange positions such that a 'Driving Force' compound is formed on the product side. The Driving Force compound is always on the product side of the equation and is a compound that takes one of three forms => A precipitating salt, a compound of a weak acid or weak base (weaker than the starting acid or base) or gas decomposition product (~ vinegar + backing soda rxn => CO₂ gas).

For your problem, split the compound into cations and anions. You can usually tell which is which by using this format on formulas like those listed in your question => reading formula from left to right, place an imaginary line after the 1st metal => this metal will be the cation & the remaining formula will be the anion.

KBr => K | Br => K (Potassium) is the cation (K⁺) and Br (Bromide) is the anion (Br⁻)

KBr => K⁺ + Br⁻

Now. Apply this rule => Add 'H' to anion => HBr, then add 'OH' to cation => KOH.

HBr is the acid and KOH is the base. Therefore ...

Acid + Base => Salt + Wk Electrolyte

HBr + KOH => KBr + H₂O (note how ions of reactants exchange places to form products).

So, KBr comes from the reaction of acid HBr and base KOH.

HBr + KOH => KBr + H₂O

To determine the acid and base origins of LiCl and NaF, use the same logic. Hope this helps. Doc :-)

7 0

3 years ago