Question

Type the correct answer in the box. Express your answer to three significant figures.

Answer 1

Answer: Theoretical mass of sodium sulphate ( $Na_2SO_4$ ) is 514.118 grams.

Explanation: For a given reaction,

$2NaOH(aq.)+H_2SO_4(aq.)\rightarrow Na_2SO_4(s)+2H_2O(l)$

As NaOH is used in excess, therefore it is an excess reagent and $H_2SO_4$ is a limiting reagent as the quantity of the product will depend on it.

We are given 355 grams of $H_2SO_4$.

Molar mass of $H_2SO_4$ = 98.079 g/mol

Molar mass of $Na_2SO_4$ = 142.04 g/mol

1 mole of $H_2SO_4$ is producing 1 mole of $Na_2SO_4$, so

98.079 g/mol of  $H_2SO_4$ will produce 142.04 g/mol of $Na_2SO_4$

355 grams of $H_2SO_4$ will produce = $142.04g/mol \times \frac{355g}{98.079g/mol}$ of $Na_2SO_4$

Mass of $Na_2SO_4$ = 514.118 grams

Answer 2

Answer:

its 514

Explanation: