76.1 gram = 1 mole of CS2
since CS2 contains 2 moles of S
the 76.1 gram of CS2 will contain the 2 mole of S atoms
<span>the rocky mountains, alps, Andes and himalas formed</span>
We are given with a theoretical amount of 9 grams of product but the student only got 7.8 grams. To calculate the percent yield, we divide the experimental amount by the theoretical amount. In this case, we divide 7.8 grams by 9 grams and multiply by 100 percent. The answer is equal to 86.67 percent.
Answer:
Volume also reduced to half
Explanation:
Volume and absolute temperature are directly proportional to each others
Answer:
0.2625L
Explanation:
Given parameters":
Volume of solution = 1.25L
Percentage concentration = 21%
Unknown:
Volume of methanol = ?
Solution:
The percentage concentration is one of the different methods for expressing concentration values.
It is given as:
Percentage concentration = ![\frac{Volume of solute}{volume of solution} x 100](https://tex.z-dn.net/?f=%5Cfrac%7BVolume%20of%20solute%7D%7Bvolume%20of%20solution%7D%20%20x%20100)
Now we have to work backwards to derive the percentage concentration;
let the unknown, the volume of methanol which is the solute = P;
21 =
x 100
21 = ![\frac{100p}{1.25}](https://tex.z-dn.net/?f=%5Cfrac%7B100p%7D%7B1.25%7D)
21 = 80p
p = 0.2625L