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3 years ago

What is the mass of KNO3(s) that must dissolve in 100. grams of water to form a saturated solution at 50.oC?

2 answers:

5 0

First, you need to check the solubility of salt table to get the solubility of KNO3(s) at 50℃. The solubility is 84g/100g which means you need 84 g KNO3 dissolving in 100 g water to make saturated solution.

Ostrovityanka [42]3 years ago

4 0

The solubility of substance depends upon the temperature. In present case, the solubility of KCl is 84g/100g at <span>50.oC.

This means that, maximum 84g of KCl can be dissolved in 100g of water (at </span>50.oC) to form solution. This solution is referred as saturated solution.

Thus, 84g of <span>KNO3 must be dissolve in 100 grams of water to form a saturated solution at 50 oC.</span>

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

aleksandr82 [10.1K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 13.83 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.300 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.300M=\frac{\text{Moles of NaI}}{0.200L}\\\\\text{Moles of NaI}=(0.300mol/L\times 0.200L)=0.06mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.06 moles of NaI will produce = $\frac{1}{2}\times 0.06=0.03mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.03 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.03mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.03mol\times 461.1g/mol)=13.83g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 13.83 grams

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3 years ago

Which describe beta decay? check all that apply. in beta decay, a proton becomes a neutron and a positron. in beta decay, a neut

kiruha [24]

The statements which best describe beta decay are: option 1, 2 and 4.

<h3>What is a beta particle?</h3>

A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a -1 charge.

Based on scientific information and records from radioactivity, we can infer that the statements which best describe beta decay are:

During beta decay, an atom of proton becomes a neutron and a positron.

During beta decay, an atom of neutron becomes a proton and an electron.

Beta decay releases energy.

Read more on beta decay here: brainly.com/question/12448836

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1 year ago

Which scale is never used by scientists?

alukav5142 [94]

Answer:

Fahrenheit

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Scientists would use Kelvin, and occasionally, Celsius scales. They do this because they need a scale that goes Sub-zero. Sub-zero temperatures are below 0° centigrade or, in the United States, below 0° Fahrenheit.

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3 years ago

2 upper N upper O subscript 2 (g) right arrow 2 upper N upper o (g) plus upper O subscript 2 (g). Second: 2 upper N upper O (g)

Ipatiy [6.2K]

The equation for the overall reaction obtained by adding these equations is; 2NO₂(g) ⇒ N₂O₄(g)

<h3>How to simplify chemical equations?</h3>

We are given equations;

2NO₂(g) ----> 2NO(g) + O₂(g) ---(1)

2NO(g) -----> N₂(g) + O₂(g) -----(2)

N₂(g) + 2O₂(g) ----> N₂O₄(g) -----(3)

Add eq 1 and eq 2 to get;

2NO₂(g) + 2NO(g) ⇒ 2NO(g) + O₂(g) + N₂(g) + O₂(g)

2NO will cancel out to get;

2NO₂(g) ⇒ N₂(g) + 2O₂(g) -----(4)

Add eq 3 to eq 4 to get;

N₂(g) + 2O₂(g) + 2NO₂(g) ⇒ N₂O₄(g) + N₂(g) + 2O₂(g)

This will reduce to;

2NO₂(g) ⇒ N₂O₄(g)

The correct question is;

Consider the chemical equations shown here.

2NO₂(g) ----> 2NO(g) + O₂(g)

2NO(g) -----> N₂(g) + O₂(g)

N₂(g) + 2O(g) ----> N₂O₄(g)

What is the equation for the overall reaction obtained by adding these equations?

Read more about chemical equations at; brainly.com/question/19837884

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1 year ago