There is no solution. Here is the explanation with both of the methods :)
Answer:Consider the Set A = {X | X is an even whole number between 0 and 2 } = .
Since, whole numbers are the set of numbers starting from zero upto infinity.
Even numbers are the numbers which are exactly divisible by '2'.
So, we have to find the even whole number between 0 and 2.
Since, only '1' is a whole number between 0 and 2 which is not an even number as '1' is not divisible by '2'.
Therefore, there is no even whole number between 0 and 2.
So, this set is empty.
Therefore, A = { X | X is an even whole number between 0 and 2} =
Step-by-step explanation:
2a^2b^3(4a^2+3ab^2-ab)=?
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is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
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Diversification is putting more money into more then one investment
