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kotegsom [21]
3 years ago
5

Answer fast DONT scam

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

the answer would be D

Step-by-step explanation:

it world be D it makes the most sence

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One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi
Elena L [17]

-16.8 = m(4)

-16.8 / 4 = -4.2

So the constant rate is -4.2.

Hope this Helps!!

4 0
3 years ago
How can 8 students share a pizza cut into 12 slices without cutting any of the slices?
Triss [41]
Hmmm...
We have to divide 12 by 8, since we need to see how 8 students will share 12 slices.

12/8=1 and 1/2

So, each student can have a slice and a half, but since we aren't allowed to cut the slices...

We can let each student have one slice, with 4 left over, so...

Every student can have one slice, and then half can have a second slice :)!

I'm not sure if that is what was meant by the question, but that was all I could think of.

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3 0
4 years ago
Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 15. Write V in component f
Scilla [17]

Answer:

a=9.641, b=11.49

Vector will be 9.641 i + 11.49 j

Step-by-step explanation:

We have given that vector V has the magnitude of 15

And it makes an angle of 50^{\circ} with positive x axis

Now let the x component of vector V is a and y component of vector V is b

So a=Vcos\Theta =15\times cos50^{\circ}=9.641

b=Vsin\Theta =15\times sin50^{\circ}=11.49

In vector form 9.641 i+11.49 j

8 0
3 years ago
A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t
alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula d=t^2+2t expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

\text{Average change}=\frac{f(b)-f(a)}{b-a}

\text{Average change}=\frac{d(5)-d(1)}{5-1}

\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}

\text{Average change}=\frac{25+10-(1+2)}{4}

\text{Average change}=\frac{35-3}{4}\\\\\text{Average change}=\frac{32}{4}\\\\\text{Average change}=8

Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

8 0
3 years ago
Hello please answer need for homework
NNADVOKAT [17]
What’s your question to ur homework
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2 years ago
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