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4 years ago

Find f(-3) if f(x) = x 2. -9 -6 6 9

Mathematics

2 answers:

Stella [2.4K]4 years ago

6 0

The answer would be -6 as far as I know

Contact [7]4 years ago

3 0

Answer:

I did this and said 9 and I got it right.

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Answer:

3802 8/9

Step-by-step explanation:

So what you do is you make 52 1/3 and 72 2/3 improper fractions like 157/3 and 218/3. Then you multiply and get 34218/9. Then you simplafiy and get 3802 8/9

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4 years ago

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13 is subtracted from the product of 4 and a certain number. The result is equal to the sum of 5 and the original number. Find t

alexira [117]

Answer:

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Step-by-step explanation:

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3 years ago

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Elan Coil [88]

Answer:

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Step-by-step explanation

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3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

8 0

3 years ago