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ad-work [718]
3 years ago
10

PLZ fast I will give for best

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Multiply both sides of the equation by 2

3x-4=14

Add 4

3x=18

Divide by 3

x=6

Good luck! Let me know if you need more help.

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tekilochka [14]
There are no solutions.
6 0
3 years ago
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Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
Question 1
Nastasia [14]

Answer:

1 zillionaire rbdgdhdndimoobenh

6 0
3 years ago
Pls help I’m being timed
rjkz [21]

Answer:

B. M-prime (4,-3)

Step-by-step explanation:

When rotated clockwise, point (h,k) is changed to point (k,-h).

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A die is rolled once what is the probability of rolling not a 4
snow_lady [41]

Answer:

I think 1/6

Step-by-step explanation:

A die has 6 sides so every side has 1/6 chance to land on

8 0
3 years ago
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