With mental math, you can perform equations quickly and efficiently. They also help you to develop your own strategies and solve more complex math equations. Hope this helps;)
I cannot suggest anything other than the set of real numbers here, but maybe someone else can provide a better answer. As long as you increase or decrease x (which is a real number) then you will get a real number, or the infinite set of real numbers.
The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
#SPJ1
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
What variable expression should you subtract from both sides of the equation so that you are left with no variables on the right-hand side?
The variable expression is: subtract 5x from both sides so that you are left with no variables on the right-hand side
![\begin{gathered} 6x\text{ - 10 = 5x + 15} \\ \text{Subtract 5 x from both sides, we have that:} \\ 6x\text{ - 5x - 10 = 5x - 5x + 15} \\ x\text{ - 10 = 15} \\ \text{Now, add 10 to both sides, we have that:} \\ x\text{ - 10 + 10 = 15 + 10} \\ x\text{ = 25} \\ \text{check:} \\ 6x\text{ - 10 = 5x + 15} \\ \sin ce,\text{ x = 25 , we have that:} \\ 6(25)\text{ - 10 = 5(25) + 15 } \\ 150\text{ - 10 = 125+ 15= 140 ( COR}\R ECT) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%206x%5Ctext%7B%20-%2010%20%3D%205x%20%2B%2015%7D%20%5C%5C%20%5Ctext%7BSubtract%205%20x%20from%20both%20sides%2C%20we%20have%20that%3A%7D%20%5C%5C%206x%5Ctext%7B%20-%205x%20-%2010%20%3D%205x%20-%205x%20%2B%2015%7D%20%5C%5C%20x%5Ctext%7B%20-%2010%20%3D%2015%7D%20%5C%5C%20%5Ctext%7BNow%2C%20add%2010%20to%20both%20sides%2C%20we%20have%20that%3A%7D%20%5C%5C%20x%5Ctext%7B%20-%2010%20%2B%2010%20%3D%2015%20%2B%2010%7D%20%5C%5C%20x%5Ctext%7B%20%3D%2025%7D%20%5C%5C%20%5Ctext%7Bcheck%3A%7D%20%5C%5C%206x%5Ctext%7B%20-%2010%20%3D%205x%20%2B%2015%7D%20%5C%5C%20%5Csin%20ce%2C%5Ctext%7B%20x%20%3D%2025%20%2C%20we%20have%20that%3A%7D%20%5C%5C%206%2825%29%5Ctext%7B%20-%2010%20%3D%205%2825%29%20%2B%2015%20%7D%20%5C%5C%20150%5Ctext%7B%20-%2010%20%3D%20125%2B%2015%3D%20140%20%28%20COR%7D%5CR%20ECT%29%20%5Cend%7Bgathered%7D)
CONCLUSION:
The final answer is:
![x\text{ = 25}](https://tex.z-dn.net/?f=x%5Ctext%7B%20%3D%2025%7D)