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VladimirAG [237]
3 years ago
6

What are the coordinates of the roots of the equation x^2+ 4x + 3 = 0 ?​

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

Step-by-step explanation:

1) Factor out the x components of the equation

(x+3)(x+1)=0

2) Take each individual term and find the value for which the equation equals zero:

x+3=0 -> x=-3

x+1=0 -> x=-1

x = -3, -1

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The number of knots in a particular type of wood has a Poisson distribution with an average of 1.6 knots in 10 cubic feet of the
HACTEHA [7]

Answer:

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

1.6 knots in 10 cubic feet of the wood.

This means that \mu = 1.6

Find the probability that a 10-cubic-foot block of the wood has at most 5 knots.

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.6}*(1.6)^{0}}{(0)!} = 0.202

P(X = 1) = \frac{e^{-1.6}*(1.6)^{1}}{(1)!} = 0.323

P(X = 2) = \frac{e^{-1.6}*(1.6)^{2}}{(2)!} = 0.258

P(X = 3) = \frac{e^{-1.6}*(1.6)^{3}}{(3)!} = 0.138

P(X = 4) = \frac{e^{-1.6}*(1.6)^{4}}{(4)!} = 0.055

P(X = 5) = \frac{e^{-1.6}*(1.6)^{5}}{(5)!} = 0.018

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.202 + 0.323 + 0.258 + 0.138 + 0.055 + 0.018 = 0.994

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

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As the question points out, the equation is indeed separable:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{6x+9}{12y^2+16y+6}

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Integrate both sides to get

2(2y^3+4y^2+3y)=3(x^2+3x)+C

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Step-by-step explanation:

Given

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Answer:

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