Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
1 answer:
Answer:
t = 3.156
Step-by-step explanation:
N = 9
Please check attachment for the table
ED = 89
ED² = 1587
Bar D = 89/9
= 9.8889
The standard deviation s
= √14283-7921/81
= √78.5432
S = 8.8625
The test statistic
= 9.8889/8.8625/√9-1
= 9.8889/3.1334
= 3.156
From the calculations above, the calculated test statistic t is = 3.156.
Please check the attachment for a more detailed solution to this problem.
Thank you!
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Answer:
So on this case the 95% confidence interval would be given by (38.608;39.392)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
represent the population standard deviation
n=25 represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
The margin of error is given by:
Since the Confidence is 0.95 or 95%, the value of and
, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that
And replacing we got:
Now we have everything in order to replace into formula (1):
So on this case the 95% confidence interval would be given by (38.608;39.392)