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elena55 [62]
3 years ago
13

How long does it take anya to cover the distance of 5.00 miles ?

Physics
1 answer:
sammy [17]3 years ago
5 0
Here is the full information about the question. <span>Ilya and Anya each can run at a speed of 8.50mph and walk at a speed of 3.50 mph . They set off together on a route of length 5.00 miles . Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.
the calculation would be:
</span><span>
t = d / s </span>
<span>t = 2.5 (half of the total distance) / 8.5 (speed of running) </span>
<span>This is .294 hours which is about 1058s... </span>

<span>for the walking part... </span>

<span>t = d / s </span>
<span>t = 2.5 / 3.5 </span>
<span>t = 5/7hours = 2571 s. </span>
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Blababa [14]

#1

As we know that

Y = \frac{stress}{strain}

now plug in all data into this

1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}

strain = 9.33 \times 10^{-3}

now from the formula of strain

strain = \frac{\Delta L}{L}

9.33 \times 10^{-3} = \frac{\Delta L}{0.54}

\Delta L = 5.04 \times 10^{-3} m

\Delta L = 5.04 mm

#2

As we know that

pressure * area = Force

here we know that

Area = 3.53 \times 11.6 = 40.95 m^2

P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa

now force is given as

F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N

#3

As we know that density of water will vary with the height as given below

\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}

here we know that

\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa

B = 2.3 \times 10^9 N/m^2

now density is given as

\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}

\rho = 1185.3 kg/m^3

#4

as we know that pressure changes with depth as per following equation

P = P_o + \rho g h

here we know that

P = 3 P_0

now we will have

3P_0 = P_0 + \rho g h

2P_0 = \rho g h

2(1.01 \times 10^5) = 1025 (9.81)(h)

here we will have

h = 20.1 m

so it is 20.1 m below the surface

#5

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

mg = \rho_1V_1g + \rho_2V_2g

A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)

46.6 = 43.89 - 922x + 1000x

x = 3.48 cm

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5 0
3 years ago
A car travels in a straight line from a position 50 m to your right to a position 210 m to your right in 5 sec. a. What is the a
Verizon [17]

Answer:

a) The average velocity is 32 m/s

b) See the attached figure. Slope of the line = 32.

Graphic: a line that passes through the points (0; 50) and (5; 210)

Explanation:

a) The average velocity is calculated as the displacement over time:

v = ΔX / Δt

where

ΔX : displacement ( final position - initial position)

Δt : time (final time - initial time)

Considering the origin of the reference system as the position where the observer is:

ΔX = 210 m - 50 m = 160 m

Δt  = 5 s

v = 160 m / 5 s = 32 m/s

b) In the graphic position vs time, plot a line that passes through the points (0, 50) (because at time 0, the car is 50 m away from you, the center of the reference system) and (5, 210). The x-axis, time, is in seconds and the y-axis, position, in meters. The slope of the line is calculated as:

slope = (X₂ - X₁) /(t₂ - t₁) = (210 - 50) / (5 - 0) = 32. Then, the velocity is equal to the slope of the line. See the attached figure.

4 0
3 years ago
To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E    ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma  .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

a=\frac{qE}{m}

Substitute the values of q, E and m in the above equation.

a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

 

6 0
3 years ago
(a) Calculate the linear acceleration of a car, the 0.220-m radius tires of which have an angular acceleration of 11.0 rad/s2. A
Alisiya [41]

Answer:

The value is  a_t =  2.42 \  m/s^2

Explanation:

From the question we are told that

  The radius of the tires is  r =  0.22 \  m

   The  angular acceleration is  \alpha  =  11.0 \ rad/s^2

Generally the linear acceleration is mathematically represented as

     a_t =  r *  \alpha

=>  a_t =  0.22  *  11

=>  a_t =  2.42 \  m/s^2

8 0
3 years ago
A car travels in a flat circle of radius R. At a certain instant the velocity of the car is 24 m/s west and the total accelerati
lisov135 [29]

Answer with Explanation:

We are given that

Velocity,v=24 m/s west

Acceleration,a=2.5m/s^2

\theta=53^{\circ}(N of W)

Horizontal component of acceleration=Tangential acceleration

Tangential acceleration,a_x=acos\theta=2.5cos53=1.505 m/s^2

Radial acceleration=Vertical acceleration=a_y=asin\theta

a_y=2.5sin53=1.998 m/s^2

Radial acceleration,a_y=\frac{v^2}{R}

1.998=\frac{(24)^2}{R}

R=\frac{(24)^2}{1.998}

R=288.29 m

Time,t=\frac{2\pi R}{velocity}

t=\frac{2\pi(288.29)}{24}

t=75.47 s

8 0
3 years ago
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