Calculate the mass number of an atom with 8 protons, 12 neutrons and 10 electrons

Physics

1 answer:

Radda [10]3 years ago

7 0

Answer: 20

Explanation: Mass number is the number of neutrons plus the number of protons. 8 + 12 gives 20.

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How does free energy challenge the scientific definition of energy?

gtnhenbr [62]

<span>Free Energy is a thermodynamic quantity given by the subtraction between the internal energy of a system and the product of its absolute temperature and entropy.
</span><span> In physics, the ability to do work.
</span>
I may not be completely sure but compare those 2 things together and you should find your answer.

7 0

3 years ago

Approximating the eye as a single thin lens 2.70 cm from the retina, find the focal length of the eye when it is focused on an o

Daniel [21]

The focal length will be = 2.67 cm

The distance between the convex lens or a concave mirror and the focal point of a lens or mirror is called the focal length. It is the point where parallel rays of light meet or converge.

given

u (object distance) = 260 cm

v (image distance) = 2.70 cm

f (focal length) = ?

using lens formula

1/f = 1/u + 1/v

= 1/260 + 1/2.70

= 2.67 cm

The focal length will be = 2.67 cm

To learn more about focal length here

brainly.com/question/14104969

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2 years ago

A closed curve encircles several conductors. The line integral around this curve is (image attached below)

Masteriza [31]

The net current in the conductors and the value of the line integral

$I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A$
The resultant remains same 3.2 *10^4 Tm

This is further explained below.

<h3>What is the net current in the conductors?</h3>

Generally,

To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).

$\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 \iint_S \mathbf{J} \cdot \mathrm{d}\mathbf{S} = \mu_0I_\mathrm{enc}$

$I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A$

In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.

The resultant remains the same at 3.2 *10^4 Tm