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bixtya [17]
3 years ago
5

Compare and contrast speed and velocity

Physics
1 answer:
Alex73 [517]3 years ago
8 0
Where speed is distance/time, velocity is displacement/time. 

What this means is that velocity is the length covered in relation to the starting point. 
Speed is just the distance travelled no matter where you began. 

When going around a circular track, you might have a speed value. However, since you get back to the same location at every lap, you have 0 velocity. 

Hope I helped :)
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If the total time is 120 seconds and the total distance is 320 meters. Calculate
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S=D/T

320/120= 2.66 miles

Explanation:

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Which automobile is faster a chevrolet or a ford? Also explain pls
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Motor oil , with a viscosity of 0 . 250 Ns / m2 , is flowing through a tube that has a radius of 5 . 00 mm and is 25 . 0 cm long
Thepotemich [5.8K]

Answer:

1.1775 x 10^-3 m^3 /s

Explanation:

viscosity, η = 0.250 Ns/m^2

radius, r = 5 mm = 5 x 10^-3 m

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According to the Poisuellie's formula

Volume flow per unit time is

V=\frac{\pi \times Pr^{4}}{8\eta l}

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V = 1.1775 x 10^-3 m^3 /s

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Write two units for electric field intensity and show thier equivalence?​
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(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a
GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

  • The distance to go between airports A and C  is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

               R = Ra x² + y²

               R =   10³

               R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

               v = \frac{\Delta y }{t}

                t = \frac{\Delta y}{v}

They ask for the time in in from airport A to B, we calculate

                t = 360 10 ^ 3/170

                t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

  • The distance to go between airports A and C B is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

5 0
3 years ago
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