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3 years ago

What is 2m + 3m² - 4m ? Please show you work. :-)

1 answer:

6 0

Combine like terms
2m and -4m are like terms while 3m^2 isnt. So, leave 3m^2 as it is and combine the other set. 2m-4m = (-2m). Therefore, your answer should be 3m^2 - 2m

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I learn maths and I don't know how to solve this problem.

Lyrx [107]

Answer:

As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.

Step-by-step explanation:

In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.

In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.

We let x=-3 for the top equation.

$( - 3) {}^{2} - 10 = - 1$

So we set the second equation equal to -1.

$- ( {x}^{2} ) + c = - 1$

$- ( - 3 {}^{2} ) + c = - 1$

$- 9 + c = - 1$

$c = 8$

So the value of c is 8. We can prove this by graphing as well.

5 0

3 years ago

What is the common reason for filing a 1040x

belka [17]

File a Form 1040-X to amend a tax return.

8 0

3 years ago

Need help with trigonometry

vovangra [49]

Answer:

$\sf \tan(A) & =\dfrac{9\sqrt{22}}{44}$

Step-by-step explanation:

If angle C is the right angle, then side c is the hypotenuse.

Use Pythagoras' Theorem $a^2+b^2=c^2$ to find the length of side a:

Given:

b = 2√22
c = 13

$\implies a^2+(2 \sqrt{22})^2=13^2$

$\implies a^2+88=169$

$\implies a^2=81$

$\implies a=\sqrt{81}$

$\implies a=9$

<u>Tan Trig Ratio</u>

$\sf \tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle

Given:

$\theta$ = A
O = side opposite angle A = a = 9
A = side adjacent angle A = b = 2√22

$\begin{aligned}\implies \sf \tan(A) & =\dfrac{9}{2\sqrt{22}}\\\\ & =\dfrac{9}{2\sqrt{22}} \times \dfrac{\sqrt{22}}{\sqrt{22}}\\\\ & = \dfrac{9\sqrt{22}}{44} \end{aligned}$