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Aleonysh [2.5K]
3 years ago
6

PLEASE HELP I WILL MARK BRAINLIEST

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

That would be wrong becuase its starting on march 2nd not March 1st, if march 1st, then it would be resoanble if she used both machines during the same day. It would be on the 17th before she uses both machines on the same day.

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Instructions: Solve the following literal equation.<br> Solve P-2w/2= l for P.
mrs_skeptik [129]

Answer:

P=l+w

Step-by-step explanation:

Solve for P by simplifying both sides of the equation, then isolating the variable.

6 0
3 years ago
How can I solve this proof?? PLZ HELP I DONT UNDERSTAND!! Thanks !!
love history [14]

Hello from MrBillDoesMath!

Answer:

See below


Discussion:

Triangles BAD and BCD are congruent by the SAS postulate.

          * Side AD = DC because BD is the perpendicular bisector  of AC.

          * Angle ADB and CDB are both right angles, and hence equal, because

            BD is the perpendicular bisector of AC)


Corresponding parts of congruent triangles are equal so angle BAD = angle BCD,  which was to be proven.


Regards,  

MrB

8 0
3 years ago
HELP!! I WILL GIVE BRAINLIEST
FrozenT [24]

Number one: Just plot down on the number like the numbers you have. Just took the test for this.

3 0
3 years ago
Complete the table of values for y=2x squared + x
Lapatulllka [165]

Answer:

y=2x^2 + 2x - 3 x -2 -1 0 1 2

Step By Step Explanation:

The values can be find by plugging the x values in the equation which gives us the y value ,

x -2 -1 0 1 2

y 1 -3 -3 1 9

(b) Plot the points on the graph and join by a smooth curve.

(c) The line y=1 will be passing through 1 and parallel to x-axis.

(d) solve 2x^2 + 2x - 3 = 1

Subtract 1 from both the sides ,

2x^2 + 2x - 2 = 0

Factoring out the 2 from the equation ,

2(x^2 + x - 1) = 0

x^2 + x - 1 = 0

Apply the quadratic formula

x=(-1-sqrt(5))/2 and x = (-1+sqrt(5))/5

5 0
3 years ago
Write the equation of the line graphed below.
trapecia [35]
<h2>y = -0.25x + 2</h2><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
6 0
3 years ago
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