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Zepler [3.9K]
3 years ago
9

Simplify itplsss helppp​

Mathematics
1 answer:
frez [133]3 years ago
8 0
Hope it’s right
Best luck with your studying

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A right angles has 2 sides 157 and 168 what is the other length
just olya [345]

Step-by-step explanation:

we can find the length of other side by hypotenuse formula,

which is h² = a² + b²

so,

a = 157

b = 168

now after inserting the values we got,

→ h² = (157)² + (168)²

→ h = 24649 + 28224

→ h = 52,873

→ h² = √52873 = 229.94

so, length of other side is 229.94

<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em><em> </em><em>take </em><em>care</em><em> </em><em>and </em><em>may</em><em> u</em><em> have</em><em> a</em><em> great</em><em> day</em><em> </em><em>ahead!</em>

3 0
3 years ago
Is 30 and 138 relatively prime
valkas [14]
Yes, If the two numbers have no factors in common then they are relatively prime.
3 0
3 years ago
Read 2 more answers
Please show work on how to do this​
Irina-Kira [14]

Answer:

  • - 2.71

Step-by-step explanation:

  • 2· 4^{v + 4} + 20 = 32
  • 2· 4^{v + 4} = 12
  • 4^{v + 4} = 6
  • (v + 4) log 4 = log 6
  • v + 4 = log 6 / log 4
  • v + 4 = 1.29  (<em>rounded</em>)
  • v = 1.29 - 4
  • v = - 2.71
5 0
3 years ago
PLEASE PLEASE HELP!!!!
Gennadij [26K]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students
aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0
3 years ago
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