Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:
Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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Factoring – Using the Distributive Property. A factor is a number that can be divided into another number evenly. For example, the factors of 6 are 1, 2, 3, and 6. ... It means that a number outside the parentheses of an addition problem can be multiplied by each number inside the parentheses.
Answer:
A. Regular pyramid
Step-by-step explanation:
If it has a vertex over the centre of the base, it has to be a pyramid.
Also, since the base is a regular polygon, the solid is a regular pyramid.
Answer:
Approximately , there are 233 animals in the forest.
Step-by-step explanation:
There was a capture program of animals to get a count of the animals in that region.There were two rounds for that program. In the first round 70 animals were captured and all of them were tagged . In the second round , there were more animals caught but only 30% of those newly caught animals had tags.
Here we have to assume that no animal loses tag.
Let the total population be x .
Then 30% of the total population is 70.
Writing equation ,
x =233 animals
Approximately , there are 233 animals in the forest.