Javier is considering two options for college.
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The 90% confidence interval is between R96.94 and R105.06
The confidence (C) = 90% = 0.9, Mean (μ) = 101, standard deviation (σ) = 39, sample size (n) = 250
α = 1 - C = 1 - 0.9 = 0.1
α/2 = 0.1 / 2 = 0.05
The z score of α/2 corresponds with the z score of 0.45 (0.5 - 0.05) which is equal to 1.645
The margin of error (E) is given by:
The confidence interval = μ ± E = 101 ± 4.06 = (96.94, 105.06)
Therefore the 90% confidence interval is between R96.94 and R105.06
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