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asambeis [7]
2 years ago
6

Javier is considering two options for college.

Mathematics
2 answers:
Galina-37 [17]2 years ago
6 0

Answer:

A

Step-by-step explanation:

Rufina [12.5K]2 years ago
3 0

Answer:

A

Step-by-step explanation:

I got it right in Edginuity.

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Car is moving on a circle on a plane. At time t (seconds), its x-coordinate is given by x(t) = 10 sin(200t + 3) + 30 while its y
Aleks [24]

Answer:

we have centre of circle as (30,40) and radius = 1

Step-by-step explanation:

Given that a car is moving on a circle on a plane.

At time t (seconds),

x(t) = 10 sin(200t + 3) + 30

and

y(t) = 10 cos(200t + 3) + 40

x-30 = 10 sin(200t + 3) \\y-40 = 10 cos(200t + 3) + 40

when we square and add both the equations we get

(x-30)^2 + (y-40)^2 = 1

(since sin square + cos square = 1 always)

i.e. we have centre of circle as (30,40) and radius = 1

3 0
3 years ago
105,159 rounded to the nearest ten thousand
Dima020 [189]
105,159 rounded to the nearest ten thousand is 100,000
8 0
3 years ago
Read 2 more answers
What conic section is drawn by the parametric equations x=csc t and y cot?
Vanyuwa [196]
If we take the square of x and square of y and then subtract them:
                         (csc t)²-(cot t)²=1                      ( this eq. gets from basic identity 
                               x²-y²=1......a                                               1+cot²x=csc²x)
  
 equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)

So, option D is correct
3 0
3 years ago
Point A lies on the circle and has an x-coordinate of 1.
scoundrel [369]

Answer:

D

Step-by-step explanation:

edg

8 0
3 years ago
Read 2 more answers
A circle has a diameter of 12 units, and its center lies on the x-axis. What could be the equation of the circle?
ycow [4]

Answer:

x^{2} +y^{2} =36

Step-by-step explanation:

A circle centered at (0,0) with radius r is x^{2} +y^{2} =r^{2}

Since your circle has diameter of 12, then its radius is 6.  Then r^{2} =36

So a possible answer is:  x^{2} +y^{2} =36

If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

(x+4)^{2} +y^{2} =36

The center of this circle would be (-4, 0) which is still on the x-axis.

8 0
3 years ago
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