Answer:
we have centre of circle as (30,40) and radius = 1
Step-by-step explanation:
Given that a car is moving on a circle on a plane.
At time t (seconds),

and


when we square and add both the equations we get

(since sin square + cos square = 1 always)
i.e. we have centre of circle as (30,40) and radius = 1
105,159 rounded to the nearest ten thousand is 100,000
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer:
D
Step-by-step explanation:
edg
Answer:

Step-by-step explanation:
A circle centered at (0,0) with radius r is 
Since your circle has diameter of 12, then its radius is 6. Then 
So a possible answer is: 
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

The center of this circle would be (-4, 0) which is still on the x-axis.