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2 years ago

JAVA...Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.

Computers and Technology

1 answer:

scoray [572]2 years ago

3 0

Answer:

RecursiveCalls.backwardsAlphabet(startingLetter);

Explanation:

The statement that is needed is a single-line statement. Since the class RecursiveCalls is already in the same file we can simply use that class and call its function without making a new class object. Once we call that class' function we simply pass the variable startingLetter (which is already provided) as the sole parameter for the function in order for it to run and use the letter 'z' as the starting point.

RecursiveCalls.backwardsAlphabet(startingLetter);

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DerKrebs [107]

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3 years ago

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Bas_tet [7]

Answer:

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Explanation:

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3 years ago

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3 years ago

Read 2 more answers

Write a second convertToInches() with two double parameters, numFeet and numInches, that returns the total number of inches. Ex:

mixer [17]

Answer:

public static double convertToInches(double numFeet, double numInches){

return (numFeet*12)+numInches;

}

Explanation:

This technique of having more than one method/function having the same name but with different parameter list is called method overloading. When the method is called, the compiler differentiates between them by the supplied parameters. The complete program is given below

public class FunctionOverloadToInches {

public static void main(String[] args) {

double totInches = 0.0;

totInches = convertToInches(4.0, 6.0);

System.out.println("4.0, 6.0 yields " + totInches);

totInches = convertToInches(5.9);

System.out.println("5.9 yields " + totInches);

return;

}

public static double convertToInches(double numFeet)

{

return numFeet * 12.0;

}

/* Your solution goes here */

public static double convertToInches(double numFeet, double numInches){

return (numFeet*12)+numInches;

}

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3 years ago

Consider a pipelined than can issue up to one instruction per cycle, but fewer may be issued because of pipeline hazards, multi-

a_sh-v [17]

Answer:

Achieved Instruction per cycle rate is $4.11\times 10^{15}$

Solution:

As per the question:

Execution time, t = 1.4 s

No. of instructions being executed, n = 1.8 billion =

Clock speed of CPU, f = 3.2 GHz = $3.2\times 10^{9} Hz$

Now, to calculate the actual issue rate achieved:

CPI (Cycle per Instruction) = $\frac{t}{n\times f}$

CPI = $\frac{1.4}{1.8\times 10^{6}\times 3.2\times 10^{9}}$

Instruction per cycle is given as the reciprocal of CPI:

Instruction per cycle = $\frac{1.8\times 10^{6}\times 3.2\times 10^{9}}{1.4} = 4.11\times 10^{15}$

6 0

3 years ago