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AlexFokin [52]
2 years ago
6

How do proportions work?

Mathematics
2 answers:
Sergio [31]2 years ago
8 0

Answer:

A proportion is simply a statement that two ratios are equal. It can be written in two ways: as two equal fractions a/b = c/d; or using a colon, a:b = c:d. The following proportion is read as "twenty is to twenty-five as four is to five."

Step-by-step explanation:

Aliun [14]2 years ago
4 0

Answer: The proportion is just a  simply  statement that two ratios are equal and  It can be written in two ways: as two equal fractions a/b = c/d; or using a colon a:b = c:d. The following proportion is read as twenty is to twenty-five as four is to five.

Step-by-step explanation:

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7 cos x+1=6 secx solve for x
jonny [76]
7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
6 0
2 years ago
Sarah bought 96 pencils and 84 erasers to make gift bags for her friends.
Alexeev081 [22]

Answer:

C. 12

Step-by-step explanation:

the greatest common factor between 84 and 96 is 12

3 0
3 years ago
Read 2 more answers
Please help pls pls help pls belp
Delvig [45]

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Step-by-step explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

8 0
2 years ago
Find the half range Fourier sine series of the function
worty [1.4K]
The full range is -\pi (length 2L=2\pi), so the half range is L=\pi. The half range sine series would then be given by

f(x)=\displaystyle\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L=\sum_{n\ge1}b_n\sin nx

where

b_n=\displaystyle\frac2L\int_0^Lf(x)\sin\dfrac{n\pi x}L\,\mathrm dx=\frac2\pi\int_0^\pi(\pi-x)\sin nx\,\mathrm dx

Essentially, this is the same as finding the Fourier series for the function

\begin{cases}g(x)=\begin{cases}\pi-x&\text{for }0

Integrating by parts yields

b_n=\dfrac2\pi\left(\dfrac\pi n-\dfrac{\sin n\pi}{n^2}\right)=\dfrac2n

So the half range sine series for this function is simply

f(x)=\displaystyle\sum_{n\ge1}\frac{2\sin nx}n
5 0
3 years ago
Please help! thanks so much​
Stels [109]

Answer:

See below.

Step-by-step explanation:

First, we can see that \lim_{x \to 2}  (f(x))= -1.

Thus, for the question, we can just plug -1 in:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  =und.

Saying undefined (or unbounded) will be correct.

However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, f(x) will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  = +\infty

This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.

4 0
3 years ago
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