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MrRa [10]
2 years ago
11

HELP SOLVE PLS. Find the Volume of the sphere shown. Give each answer rounded to the nearest cubic unit. Answer choices: 442 cm,

236 cm, 1,767 cm, & 14,137

Mathematics
1 answer:
kipiarov [429]2 years ago
4 0

Answer:

Volume of a sphere can be calculated by this equation

v=\frac{4}{3} \pi r^3

=> radius is diameter divide by 2

v=\frac{4}{3}\:\pi \:\left(\frac{15}{2}\right)^3

v=\frac{5^3\cdot \:3^2\pi }{2}

v=\frac{1125\pi }{2}

or 1767.14 cm cube

The answer is C

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(2,0) (4,5) write an equation that represents the line
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Answer:

the equation of the line in slope-intercept form would be y=5/2x-5

Step-by-step explanation:

hope this helped!! :D

4 0
3 years ago
Please help me with this answer!! I am really stuck...No nonsense answers please.
wariber [46]

Answer:

19

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

< DBG = 1/2 ( DG)

< DBG = 1/2 ( 360 - BD - BG)

           = 1/2 ( 360 - 172 - 150)

           = 1/2 (38)

           = 19

8 0
3 years ago
Can someone help me with this problem
user100 [1]

Answer:

About 110.6

Step-by-step explanation:

The sine of an angle is the length of the opposite side divided by the length of the hypotenuse.

\sin 19= \dfrac{36}{x} \\\\x=\dfrac{36}{\sin 19}\approx 110.6

Hope this helps!

5 0
3 years ago
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
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NARA [144]
The answer is.............
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4 years ago
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