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Rudiy27
3 years ago
8

Need help! Don’t understand

Chemistry
1 answer:
shtirl [24]3 years ago
8 0
Bro honestly I don’t understand either
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12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate
Lilit [14]

For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K  is mathematically given as

Ecell = 0.577 V

<h3 /><h3>What is the cell potential at 298 K?</h3>

Generally, the equation for the Oxidation and Reduction  is mathematically given as

Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O

Sn+2(aq) + 2e- ------------ Sn(s) ] x 3  ...R

Reaction

 2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)

Therefore

Eicell = - 0.14 - ( - 0.74)

Eicell = 0.60

In conclusion

Ecell= E0cell - \frac{0.0591}{n} * \frac{log[Cr+3]^2}{ [ Sn+2]^3}

Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}

Ecell = 0.577 V

Read more about Temperature

brainly.com/question/13439286

5 0
3 years ago
Atoms in 1 mol of carbon dioxide
astra-53 [7]
1 carbon and 2 oxygen atoms CO2
8 0
3 years ago
On the basis of the diagram, which of the following statements is true?
Furkat [3]
The answer is d I'm pretty sure because the second one and the first one don't make sense but I'm not 100 percent positive about it not being d ..... sorry if it's wrong.
5 0
3 years ago
Read 2 more answers
Measure the initial temperature of the water to the
LuckyWell [14K]

Answer:

Answer:

100

22.4

27.1

Explanation:

Explanation:

just did it on edge .

Hope this helps

8 0
3 years ago
Does anyone know the answers for these
Alexeev081 [22]

Answer: 1. 0.045moles

2.  2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

1. \text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles

2. Mass of C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g

4 0
3 years ago
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