Answer:
Volume of container = 0.0012 m³ or 1.2 L or 1200 ml
Explanation:
Volume of butane = 5.0 ml
density = 0.60 g/ml
Room temperature (T) = 293.15 K
Normal pressure (P) = 1 atm = 101,325 pa
Ideal gas constant (R) = 8.3145 J/mole.K)
volume of container V = ?
Solution
To find out the volume of container we use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First we find out number of moles
<em>As Mass = density × volume</em>
mass of butane = 0.60 g/ml ×5.0 ml
mass of butane = 3 g
now find out number of moles (n)
n = mass / molar mass
n = 3 g / 58.12 g/mol
n = 0.05 mol
Now put all values in ideal gas equation
<em>PV = nRt</em>
<em>V = nRT/P</em>
V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa
V = 121.87 ÷ 101,325 pa
V = 0.0012 m³ OR 1.2 L OR 1200 ml
Answer:
Molality = 1.46 molal
The freezing point of the solution = -2.72 °C
Explanation:
Step 1: Data given
The freezing point of water H2O is 0.00°C at 1 atmosphere
urea = nonelectrolyte = van't Hoff factor = 1
Mass urea = 13.40 grams
Molar mass urea = 60.1 g/mol
Mass of water = 153.2 grams
Molar mass H2O = 18.02 g/mol
Kf = 1.86 °C/m
Step 2: Calculate moles urea
Moles urea = mass urea /molar mass urea
Moles urea = 13.40 grams / 60.1 g/mol
Moles urea = 0.223 moles
Step 3: Calculate the molality
Molality = moles urea / mass water
Molality = 0.223 moles / 0.1532 kg
Molality = 1.46 molal
Step 4: Calculate the freezing point of the solution
ΔT = i * Kf * m
ΔT = 1* 1.86 °C/m * 1.46 m
ΔT = 2.72 °C
The freezing point = -2.72 °C
It is an sp hybridization
Answer:
<em>Barometers measure this pressure. ... Changes in the atmosphere, including changes in air pressure, affect the weather. Meteorologists use barometers to predict short-term changes in the weather. A rapid drop in atmospheric pressure means that a low-pressure system is arriving.</em>
Explanation:
<h3>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>!</em></h3>
The statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.
<h3>What is a pond?</h3>
Pond is an inland body of standing water, either natural or man-made, that is smaller than a lake.
A bog is an area of decayed vegetation (particularly sphagnum moss) which forms a wet spongy ground too soft for walking.
This means that a pond can become a bog when existing plants in the pond decays until the land becomes soft.
Therefore, the statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.
Learn more about ponds and bogs at: brainly.com/question/9715563
#SPJ1
