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2 years ago

Need help! Don’t understand

Chemistry

1 answer:

shtirl [24]2 years ago

8 0

Bro honestly I don’t understand either

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Explain why we use 1/12 in finding atomic mass unit ?

Nat2105 [25]

Answer:

The u (amu is the old unit name) is 1/12 of the weight of an 12C atom. The way the u is chosen ensures that all core and atom masses are multiples of 1(±0.1) u.

Explanation:

Further explanation if needed...

Carbon 12 was chosen because the chemical atomic weights based on C12 are almost identical to the chemical atomic weights based on the natural mix of oxygen. Simply because the atomic mass is defined as 1/12 of the mass of 12C. Others isotopes of carbon (13C mostly, with an abundance of 1.1% approximately) account for an average atomic mass slightly above 12.

7 0

2 years ago

Could a mixture be made up of only one element and no compounds

Firdavs [7]

Yes. A mixture can be made up of just elements without the use of a compound, you can also just use compounds in a mixture without any elements

5 0

2 years ago

The cells of plant and animals lack nuclei

Masteriza [31]

That is not true
They both have nuclei or we would not be living now

6 0

2 years ago

A student increases the temperature of a 200^3 cm balloon from 60°C to 120°C. What will the new volume of the balloon be? (Be ca

Darina [25.2K]

Explanation:

Given parameters:

Initial volume V1 = 200cm³

Initial temperature = 60°C

Final temperature = 120°C

Unknown:

Final volume = ?

Solution:

According to Charles law, at constant pressure, the volume of a given mass of gas is directly proportional to temperature.

mathematically;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

1 and 2 are the initial and final states

V is the volume and T is the temperature

convert the temperature to kelvin

T1 = 60 + 273 = 333K

T2 = 120 + 273 = 393K

Input the parameters;

$\frac{200}{333} = \frac{V_{2} }{393}$

final volume is 236cm³

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

7 0

2 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

1 Ampere = 1 Coulomb / second
The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
1 mole of Al is produced when 3 moles of electrons circulate
The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

6 0

3 years ago