6x²+x-12
the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)
two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term
6x²+9x-8x-12
now we look for whats common between the first two numbers and divide them out
6x²+9x = 3x(2x+3)
now we do the same with the last two numbers
-8x-12 = -4(2x+3)
notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside
once we do that you should get an answer of
(3x-4)(2x+3)
hope this helped!
Answer:
x = -2
x = 8
Step-by-step explanation:
Excluded values are the ones which make the denominator zero
3x² + x - 10
3x² + 6x - 5x - 10
3x(x + 2) - 5(x + 2)
(x + 2)(3x - 5)
x² - 6x - 16
x² - 8x + 2x - 16
x(x - 8) + 2(x - 8)
(x - 8)(x + 2)
[(x + 2)(3x - 5)] ÷ [(x - 8)(x + 2)]
(3x - 5)/(x - 8)
So excluded values are 8, -2
Answer:
when they cross u should get a perfect solution of (2,6)
$15
Explanation:
For each lawn he mows = $5
<u>He should mow 6 lawns but did only 3 lawns as other 3 he forgot to mow.</u>
earned:
