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o-na [289]
2 years ago
8

Can someone pls explain and do this solution:(

Mathematics
1 answer:
Orlov [11]2 years ago
6 0

Given,

SP~QP

SR~QR

In ∆SRP and ∆QRP

SP~QP (given)

SR~QR (given)

PR=PR (common)

Therefore,

∆SRP~∆QRP by SSS congruence rule.

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7+ 2x divided by 5= 13
Troyanec [42]

Answer:

x=29

Step-by-step explanation:

Given equation :

\frac{(7+2x)}{5} =13

Making the terms of 'x' to one side and constants to the other.

                   (7+2x)=13*5

                       7+2x=65

                            2x=65-7

                              2x=58

                                x=\frac{58}{2}

                                  x=29

So, the value of 'x' is 29.

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3 years ago
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what is the difference between solving problems that have dependant events versus those with independent events?
julsineya [31]
The state government said it was the president of president
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3 years ago
tomatoes are $2.75 per pound, or you can buy a 5 pound box for $11. what is the better value option?​
kozerog [31]

Answer:

The better value is 5pounds for $11

Step-by-step explanation:

2.75×5= $13.75

so the 5 pounds for $11 would be better because the other option would cost $13.75 for the same amount

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Your swimming pool containing 60,000 gal of water has been contaminated by 6 kg of a nontoxic dye that leaves a swimmer's skin a
Paul [167]

[a] Dye is removed from the pool at a rate of

(250 gal/min) * (<em>q</em>/60,000 g/gal) = -<em>q</em>/240 g/gal

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So the net rate of change of the amount of dye in the pool is given by the differential equation,

\dfrac{\mathrm dq}{\mathrm dt}=-\dfrac{q(t)}{240}

with the intial value, <em>q</em>(0) = 6000 g (or 6 kg).

[b] The ODE above is separable as

\dfrac{\mathrm dq}q=-\dfrac{\mathrm dt}{240}

Integrate both sides to get

\ln|q|=-\dfrac t{240}+C

e^{\ln|q|}=e^{-t/240+C}

\implies q(t)=e^{-t/240+C}=e^{-t/240}e^C=Ce^{-t/240}

Now plug in the initial condition:

6000=Ce^0\implies C=6000

so the particular solution to the IVP is

q(t)=6000e^{-t/240}

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1800=6000e^{-t/240}\implies0.3=e^{-t/240}

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\implies t=-240\ln0.3\approx288.953

so the amount of dye in the pool is within the acceptable tolerance after about 289 min have passes, or about 4.82 hrs. So no, the filtration system is not up to the task.

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