2 years ago

Can someone pls explain and do this solution:(

1 answer:

Orlov [11]2 years ago

6 0

Given,

SP~QP

SR~QR

In ∆SRP and ∆QRP

SP~QP (given)

SR~QR (given)

PR=PR (common)

Therefore,

∆SRP~∆QRP by SSS congruence rule.

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