Answer:
Laurie's maximum depth can be represented using the expressions :
(20 × 3) = 60
(3 × 4 × 5) = 60
Step-by-step explanation:
Each depth level at which ears are checked = 5 feets
Each Depth level at which instruments are checked = 20 feets
For Laurie to check her instrument ;
Number of times ears are checked = 20/5 = 4 times
This means that for Laurie to have checked her instrument 3 times :
(4 × 3 × 5) = 60 feets
Therefore, Laurie's maximum depth can be expressed as (4 × 3 × 5) = 60 feets
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
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<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
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<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
<h3>Answer: y = (3/2)x + 0</h3>
This is the same as y = (3/2)x
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Work Shown:
Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)
m = (y2 - y1)/(x2 - x1)
m = (3 - (-3))/(2 - (-2))
m = (3 + 3)/(2 + 2)
m = 6/4
m = 3/2
The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.
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Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.
y - y1 = m(x - x1)
y - (-3) = (3/2)(x - (-2))
y + 3 = (3/2)(x + 2)
y + 3 = (3/2)x + (3/2)(2)
y + 3 = (3/2)*x + 3
y + 3 - 3 = (3/2)*x + 3 - 3
y = (3/2)x + 0
The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.
Equation: 21+n=43.23
Process to find n
21+n=43.23
Subtract 21 from both sides
n=22.23
