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djverab [1.8K]
3 years ago
12

I need help and can you please give me the answers as well appreciate it

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

I honestly need help with this

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Geometry, any idea?
Pepsi [2]

Answer:

8

Step-by-step explanation:

15x-31+9×+11+×=180

25×-20=180

25×=200

×=8

15(8)-31=89

9(8)+11=83

8

5 0
3 years ago
20 POINTS!!!
Inga [223]

Step-by-step explanation:

I think option A is the correct answer

Because it is in ascending order

4 0
3 years ago
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What is the percent of decrease from 6 to 5.4?
Helga [31]

Answer:

The percent decrease from 6 to 5.4 is 10%.

Step-by-step explanation:

5 0
3 years ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
3 years ago
Read 2 more answers
Consider the proportion 3:4 = 6:8. What is true about the cross products?
vitfil [10]
Cross products are equal
7 0
3 years ago
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