Answer:
r=7
Step-by-step explanation:
6r-7+90+55=180
6r+138=180 ----- 6r=180-138
6r=42 ----- divide both sides by 6
r=7
(We get the 90 from the 90degrees in the middle of this supplementary angle and the total, 180, from the straight angle made from all three angles.)
hope this helps!
1.5 / 5 = .3, not sure why it says to round to nearest tenth though
Answer:
x>−3/7
Step-by-step explanation:
I hope this helps you
Implicit or Doubtful memory of actual events that was stored encrypted, but was not retrieved for a long time until subsequent events suddenly brought it back to consciousness. The establishing, stabilizing like processes include in this memory.
Implicit Memory is a type of long-term memory and it is also known as unconscious memory or automatic memory. Implicit memory draws on past experiences to remember things without thinking. The power of tacit memory is made possible by past experiences, regardless of how long ago those experiences were.
Second stage of long-term memory formation.
Implicit memory, a subset of procedural memory, allows you to perform many everyday physical activities, such as walking and cycling, without having to think about it. Most of the implicit storage is procedural in nature.
For example:
- typing on a keyboard
- brushing your teeth. Riding a bicycle
- Most people find it easy to ride a bike, even after years of not riding.
To learn more about Implicit Memory, refer:
brainly.com/question/15033888
#SPJ4
Solution :
Along the edge 
The parametric equation for is given :
Along edge 
The curve here is a quarter circle with the radius 9. Therefore, the parametric equation with the domain 
is then given by :
Along edge 
The parametric equation for is :
Now,
x = 9t, ⇒ dx = 9 dt
y = 0, ⇒ dy = 0
And
Then :
![$=\int_0^1 \left[\left( 9 \sin \frac{\pi}{2}t\right)^2\left(9 \cos \frac{\pi}{2}t\right)\left(-\frac{7 \pi}{2} \sin \frac{\pi}{2}t dt\right) + \left( 9 \cos \frac{\pi}{2}t\right)^2\left(9 \sin \frac{\pi}{2}t\right)\left(\frac{7 \pi}{2} \cos \frac{\pi}{2}t dt\right) \right]$](https://tex.z-dn.net/?f=%24%3D%5Cint_0%5E1%20%5Cleft%5B%5Cleft%28%209%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5E2%5Cleft%289%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5Cleft%28-%5Cfrac%7B7%20%5Cpi%7D%7B2%7D%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%20dt%5Cright%29%20%2B%20%5Cleft%28%209%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5E2%5Cleft%289%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5Cleft%28%5Cfrac%7B7%20%5Cpi%7D%7B2%7D%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%20dt%5Cright%29%20%5Cright%5D%24)
![$=\left[-9^4\ \frac{\cos^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} -9^4\ \frac{\sin^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} \right]_0^1$](https://tex.z-dn.net/?f=%24%3D%5Cleft%5B-9%5E4%5C%20%5Cfrac%7B%5Ccos%5E4%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%7D%7B%5Cfrac%7B%5Cpi%7D%7B2%7D%7D%20-9%5E4%5C%20%5Cfrac%7B%5Csin%5E4%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%7D%7B%5Cfrac%7B%5Cpi%7D%7B2%7D%7D%20%5Cright%5D_0%5E1%24)
= 0
And
x = 0, ⇒ dx = 0
y = 9 t, ⇒ dy = 9 dt
Therefore,
= 0 + 0 + 0
Applying the Green's theorem
Here,
Therefore,
The vector field F is = 
is conservative.
