The sum of n terms is given from the first term and the common ratio by
For your given values of a1=-11, r=-4, n=8, the sum of 8 terms is
A quadrilateral is any figure with 4 sides, no matter what the lengths of
the sides or the sizes of the angles are ... just as long as it has four straight
sides that meet and close it up.
Once you start imposing some special requirements on the lengths of
the sides, or their relationship to each other, or the size of the angles,
you start making special kinds of quadrilaterals, that have special names.
The simplest requirement of all is that there must be one pair of sides that
are parallel to each other. That makes a quadrilateral called a 'trapezoid'.
That's why a quadrilateral is not always a trapezoid.
Here are some other, more strict requirements, that make other special
quadrilaterals:
-- Two pairs of parallel sides . . . . 'parallelogram'
-- Two pairs of parallel sides
AND all angles the same size . . . . 'rectangle'
(also a special kind of parallelogram)
-- Two pairs of parallel sides
AND all sides the same length . . . 'rhombus'
(also a special kind of parallelogram)
-- Two pairs of parallel sides
AND all sides the same length
AND all angles the same size . . . . 'square'.
(also a special kind of parallelogram, rectangle, and rhombus)
Answer:
Yes, lines M and N intersect because their slopes are different.
Step-by-step explanation:
First, we can start out by finding the slope of Line M and Line N. The slope formula is (y_2 - y_1)/(x_ 2- x_1)
Slope of Line M:
(3--11) / (3--4)
(3+11) / (3+4)
14/7
2
Now we know that the slope of Line M is 2.
Slope of Line N:
(9--2) / (-6-5)
11/-11
The slope of Line N is -1!
Since the slopes of Line N and M are different, they intersect. The answer is Yes, lines M and N intersect because their slopes are different.
If the slopes were the same, Line N and M would NEVER intersect because they are parallel.
Hope this helps
