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vaieri [72.5K]
2 years ago
9

It requires energy to melt ice. Applying salt to the ice created a chemical reaction melting the ice. Were did the energy come f

rom to melt the ice? *
Chemistry
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

HOPE IT HELPS...

Explanation:

When added to ice, salt first dissolves in the film of liquid water that is always present on the surface, thereby lowering its freezing point below the ices temperature. Ice in contact with salty water therefore melts, creating more liquid water, which dissolves more salt, thereby causing more ice to melt, and so on

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The rate of effusion of a particular gas was measured and found to be 24.0 mL/min. Under the same conditions, the rate of effusi
Norma-Jean [14]

Answer:

63.6g/mol

Explanation:

Use the equation of effusion:

47.8/24=\sqrt{x/16.04}

solve for x you get 63.6g/mol

3 0
3 years ago
Alkanes are hydrocarbons that contain _____.
abruzzese [7]
I would have to say D) carbon-to-hydrogen ratio
6 0
3 years ago
An atom has atomic number 5 and mass number 11. How many protons does the atom have? 5 6 10 11
spin [16.1K]

Answer:

6 neutrons. The mass number is the number of protons and neutrons in the nucleus of an atom. The atomic number shows how many protons. Subract the atomic number from the mass number to find the number of neutrons.

Explanation:

6 0
3 years ago
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How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?
Aleksandr-060686 [28]

Answer:

V_{HCl}=5.05x10^{-3}L

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

2*n_{HCl}=n_{Ba(OH)_2}

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

Besr regards.

8 0
3 years ago
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A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your
katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

                   = 40 + 71

                   = 111 g

2.- Convert the grams to moles

                       111 g of CaCl₂ -------------- 1 mol

                         x                   ---------------0.34 mol

                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

                            x = (6.5 x 37.74) / 1

                            x = 245.31

3 0
3 years ago
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