Can someone please help asap!

Please help with an easy percentage yield question ASAP!!! Would really appreciate!

Brut [27]

Answer:

The mass percentage yield is 85%

Explanation:

<u>Step 1: </u>The balanced equation

2 C7H6O3 + (CH3CO)2CO → 2 C9H8O4 + H20

<u>Step 2</u>: Given data

mass of salicylic acid = 1.03 grams

Volume of acetic anhydride = 2.00 mL = 2*10^-3 L

The product is 1.16 g aspirin synthesized

Molar mass of salicylic acid = 138.12 g/mole

Molar mass of aspirin = 180.16 g/mole

Density of acetic anhydride = 1.0820 g/mL

<u>Step 3</u>: Calculated moles of salicylic acid

Number of moles of salicylic acid = mass of salicylic acid / Molar mass of salicylic acid

Number of moles of salicylic acid = 1.03 grams / 138.12 g/mole

Number of moles of salicylic acid =0.0075 moles

Step 4: Calculated mass acetic anhydride

mass of acetic anhydride = 1.0820 g/mL * 2 mL = 2.164 grams

Step 5: Calculate number of moles of acetic anhydride

Number of moles = 2.164 grams / 102.09 g/moles

Number of moles = 0.0212 moles

<u>Step 6</u>: Find amount of reacting moles

C7H6O3 is the limiting reactant, there will react 0.0075 moles

Since for 2 moles C7H6O3 consumed, we need 1 mole of (CH3CO)2CO to produce 2 moles of C9H804

So for 0.0075 moles C7H6O3 consumed, we produce 0.0075 moles of C9H8O4

<u>Step 7</u>: Calculate mass of aspirin

mass of aspirin = 0.0075 moles * 180 g/mole = 1.35 grams

<u>Step 8:</u> Calculate the mass percentage yield

(1.16 grams / 1.35 grams) * 100% = 85 %

The mass percentage yield is 85%

7 0

3 years ago

Importancia de las disoluciones en la vida cotidiana

Tomtit [17]

Las disoluciones son fundamentales para que se lleven a cabo las reacciones químicas que sustentan la vida. Esta es una mezcla de dos o más sustancias.

<h3>Disoluciones</h3>

Una disolución se refiere a una mezcla entre dos o más sustancias puras que da lugar a una mezcla homogénea de las mismas.

Una disolución está compuesta por al menos una sustancia conocida como disolvente (por ejemplo, agua) y al menos susutancia conocida como soluto (por ejemplo, sal).

Las disoluciones son fundamentales para una gran variedad de procesos biológicos requeridos para sustentar la vida y las reacciones metabólicas asociadas a estos procesos.

Aprende más sobre disoluciones aquí:

brainly.com/question/24003174

4 0

2 years ago

Whenever anything moves, it has _____ energy. <br><br> chemical <br> heat <br> mechanical

BaLLatris [955]

Mechanical, because the other two make no sense and mechanical energy is the combination of kinetic and potential energy, or moving and still respectively.

5 0

3 years ago

Read the scenario and then answer the question.

Dvinal [7]

Elias could be standing on the transform boundary.

Answer: Option 1.

<u>Explanation:</u>

Transform boundaries are places where plates slide sideways past one another. At change limits lithosphere is neither made nor devastated. Many change limits are found on the ocean bottom, where they associate fragments of veering mid-sea edges. California's San Andreas issue is a transform boundary.

Transform boundaries are regions where the Earth's plates move past one another, scouring along the edges. Every one of these three sorts of plate limit has its own specific kind of flaw (or break) along which movement happens. Transforms are strike-slip issues. There is no vertical movement—just horizontal.

6 0

3 years ago

When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac

slega [8]

<h2>Answer:</h2> $1.33*10^{-2}grams$

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

$\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}$

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

$\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}$

Determine the mass of water produced

$\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}$

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0

1 year ago