I need help with this so try to help me out please

Which of the following elements is only made in laboratories? sb cm te tb

liberstina [14]

Its fermium but the answer isnt on there

3 0

3 years ago

HELP POGGERS!!! I NEED HELP!!!!!!!!!! THIS IS NEEDED IN 10 MINS

frez [133]

The answer is 3 - convection.

5 0

3 years ago

Read 2 more answers

This woman comes to the clinic with high blood pressure,

Advocard [28]

I’m assuming it’s type one (most likely) diabetes!

5 0

3 years ago

Ethanol (C2H5OH) melts at –114 °C and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kJ/mol, and its enthalpy of vapo

alexandr1967 [171]

Answer:

First question

$Q = 36826 \ J$

Second question

$Q = 52299.7 \ J$

Explanation:

From the question we are told that

The melting point of Ethanol is $T_m = -114 ^oC$

The boiling point of Ethanol is $T_b = 78^ oC$

The enthalpy of fusion of Ethanol is $F = 5.02 \ kJ / mol = 5.02 *10^{3}\ kJ / mol$

The enthalpy of vaporization of Ethanol is $L = 38.56 \ kJ / mol = 38.56 *10^{3} \ J / mol$

The specific heat of solid Ethanol is $c_e = 0.97 \ J/ g \cdot K$

The specific heat of liquid Ethanol is $c_l = 2.3 \ J / g \cdot K$

The mass of the Ethanol given is $m = 35.0 \ g$

Considering the first question

The initial temperature is $T_i = 27^oC$

The final temperature is $T_f = 120^oC$

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

$Q_1 = m * c_l * (T_b - T_i)$

=> $Q_1 = 35.0 * 2.3 * ( 78 - 27)$

=> $Q_1 =4106 \ J$

Genially the number of moles of Ethanol given is mathematically represented as

$n = \frac{m}{Z}$

Here Z is the molar mass of Ethanol with value $Z = 46 g/mol$

So

$n = \frac{35}{46 }$

=> $n = 0.7609 \ mol$

Generally the heat of vaporization of the Ethanol is mathematically represented as

$Q_2 = n * L$

=> $Q_2 =0.7809 * 38.56 * 10^{3}$

=> $Q_2 =29339 \ J$

Generally the heat required too raise the Ethanol from its boiling point to $T_f$ is mathematically represented as

$Q_3 = m * c_l * (T_f - T_b)$

=> $Q_3 = 35 * 2.3 * (120 - 78 )$

=> $Q_3 = 3381 \ J$

Generally the total heat required is

$Q = Q_1 + Q_2 + Q_3$

=> $Q = 4106 + 29339 + 3381$

=> $Q = 36826 \ J$

Considering the second question

The initial temperature is $T_i = -120^oC$

The final temperature is $T_f = 120^oC$

Generally the heat required too raise the Ethanol to its melting point is mathematically represented as

$Q_1 = m * c_e * (T_m - T_i)$

=> $Q_1 = 35.0 * 0.97 * ( -114 - (- 120) )$

=> $Q_1 = 203.7 \ J$

Generally the heat of fusion of the Ethanol is mathematically represented as

$Q_2 = n * F$

=> $Q_2 =0.7809 * 5.02 *10^{3}$

=> $Q_2 =3920 \ J$

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

$Q_3 = m * c_l * (T_b - T_m)$

=> $Q_3 = 35.0 * 2.3 * ( 78 - (- 114) )$

=> $Q_3 =15456 \ J$

Generally the heat of vaporization of the Ethanol is mathematically represented as

$Q_4 = n * L$

=> $Q_4 =0.7809 * 38.56 * 10^{3}$

=> $Q_4 =29339 \ J$

Generally the heat required too raise the Ethanol from its boiling point to $T_f$ is mathematically represented as

$Q_5 = m * c_l * (T_f - T_b)$

=> $Q_5 = 35 * 2.3 * (120 - 78 )$

=> $Q_5 = 3381 \ J$

Generally the total heat required is

$Q = Q_1 + Q_2 + Q_3+Q_4 + Q_5$

=> $Q = 203.7 + 3920 + 15456 +29339+3381$

=> $Q = 52299.7 \ J$

5 0

3 years ago

I need help ASAP! How many reactants and products are in each element according to the chemical equation above. Please explain t

Nikitich [7]

Answer: 1,4,1 for the reactants
3,1,4,1 for the products

Explanation:
The products are equal to the reactants because of the conservation of matter.

6 0

3 years ago