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Gemiola [76]
3 years ago
12

To what volume will a 2.33 l sample of gas expand if it is heated from 30.0 ∘c to 300.0 ∘c?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0
According to Charle's Law,
V/T =  constant
where 
V = volume
T =  absolute temperature.

The law holds when the pressure of an ideal gas is held constant while temperature changes.

V₁ = 2.33 L, initial volume
T₁ = 30°C = 30+273 K = 303 K, initial temperature
T₂ = 300°C = 300+273 K = 573 K, final temperature

The final volume, V₂, is given by
V₂/T₂ = V₁/T₁
V₂ = (573 K)*(2.33/303  L/K)
     =  4.406 L

Answer: 4.41 L

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4 years ago
Read 2 more answers
If 3.5 moles of nitrogen monoxide (NO) react with 6.0 moles of oxygen gas (O2), how many moles of the product can be formed and
jasenka [17]

Answer: -

4.25 mol of O₂ left as excess.

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Explanation: -

Number of moles of NO taken = 3.5

Number of moles of O₂ taken = 6.0

The balanced chemical equation for this reaction is

2 NO+ O₂ → 2 NO₂

From the equation we can see that

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3.5 mol of NO gives\frac2 mol NO2}{2 mol NO} x 3.5 mol NO

= 3.5 mol of NO₂

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Hence, option D is correct.

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