To what volume will a 2.33 l sample of gas expand if it is heated from 30.0 ∘c to 300.0 ∘c?

1 answer:

3 0

According to Charle's Law,
V/T = constant
where
V = volume
T = absolute temperature.

The law holds when the pressure of an ideal gas is held constant while temperature changes.

V₁ = 2.33 L, initial volume
T₁ = 30°C = 30+273 K = 303 K, initial temperature
T₂ = 300°C = 300+273 K = 573 K, final temperature

The final volume, V₂, is given by
V₂/T₂ = V₁/T₁
V₂ = (573 K)*(2.33/303 L/K)
= 4.406 L

Answer: 4.41 L

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